我正在寫這樣的時間表模型中定義的每當跑步者;數據庫每當gem cron作業的時間比較
def self.scheduled_jobs
jobs = Schedule.where(execution_time <= Time.now)
if !jobs.nil?
jobs.each do |job|
task = Schedule.find(job)
MessageWorker.perform_async(task.message_id, task.lists, task.user_id)
task.destroy
end
end
end
這裏的查詢有問題;
jobs = Schedule.where(execution_time <= Time.now)
和建議?
在控制檯的響應是;
NameError: undefined local variable or method
execution_time」主:Object`
總體上如何提高代碼的任何建議?
每當cron工作在這裏;
set :output, "/log/cron_log.log"
every 5.minute do
runner "Schedule.scheduled_jobs"
end
用''execution_time <=?「,Time.now'代替'where'條件 – tihom