如何檢查電子郵件數據的基礎已經存在，如果再把它存在更新

Question

//queries that have to be run. 
$sql1="INSERT INTO user (userEmail,fname,lname,mobileno,designation,institution,userPassword,loginToken,userType,status,created,modified) 
VALUES ('$userEmail','$fname','$lname','$mobileno','$designation','$institution','$hash',UUID(),'$userType','active',CURRENT_TIMESTAMP(),CURRENT_TIMESTAMP())"; 

$sql2="INSERT INTO authorDetail (id,paperName,paperId,paymentStatus) 
VALUES ('$last_id', '$paperName', '$paperId', '$paymentStatus')"; 

$sql3="SELECT id FROM user WHERE userEmail = '$userEmail'"; 


echo "check 3"."<br>"; 
//connection to update the inserted data from an html form 
if (mysqli_query($connect, $sql1)) 



        { 
          $last_id = mysqli_insert_id($connect); 
          echo "New record created successfully. Last inserted ID is: " . $last_id; // code for getting the last entered data in the table 
        } 
        else 
        { 
         $lastlast_id = mysqli_insert_id($connect); 
          echo "Error: " . $sql1 . "<br>" . mysqli_error($connect); //this checks for the validation of email from the user table 
          echo "checkcheck"; 

        } 

echo "check 4"."<br>"; 

// code for updating the foreign key mapped table 

if (mysqli_query($connect, $sql2)) 
{ 
     $last_id = mysqli_insert_id($connect); 
     echo "New record created successfully. Last inserted ID is: " . $last_id; //finding the id of the last inserted data+ 
} else { 

    enter code here 

     echo "Error: " . $sql2 . "<br>" . mysqli_error($connect); 
} 
echo "check5"."<br>"; 
        mysqli_close($connect); 
echo "check 6"."<br>"; 

Answer 1

它很容易，你可以通過查詢做到這一點，

INSERT INTO t1 (a,b,c) VALUES (1,2,3) 

ON DUPLICATE KEY UPDATE c=c+1; 

來源： https://dev.mysql.com/doc/refman/5.7/en/insert-on-duplicate.html