1
我有一些基於平日數據如下:如何基於任意對象值對數組進行排序?
[{
"dayOfWeek": "TUESDAY",
"startTime": "19:30:00",
"endTime": "21:15:00"
}, {
"dayOfWeek": "SATURDAY",
"startTime": "19:15:00",
"endTime": "21:00:00"
}, {
"dayOfWeek": "FRIDAY",
"startTime": "19:00:00",
"endTime": "20:15:00"
}, {
"dayOfWeek": "THURSDAY",
"startTime": "19:15:00",
"endTime": "20:30:00"
}, {
"dayOfWeek": "WEDNESDAY",
"startTime": "19:30:00",
"endTime": "20:45:00"
}, {
"dayOfWeek": "SUNDAY",
"startTime": "19:30:00",
"endTime": "20:45:00"
}, {
"dayOfWeek": "MONDAY",
"startTime": "19:30:00",
"endTime": "21:00:00"
}]
然而,這種數據來自具有不規則分選的API,其不能被信任。我需要將這個數組從MONDAY到SUNDAY的值遞減。我怎樣才能做到這一點?我假設我必須設置某種地圖進行查找?
右鍵,創建一個對象,它的鍵是當日的名稱和它的值是0〜6(或1至7或任何你想要的),然後使用你的'的.sort( )'比較器功能。 – Pointy
查看我標記爲@Pointy提到的內容的副本 –
實際上,此副本更符合您的需求:http://stackoverflow.com/questions/34066752/sort-object-of-weekdays-like-sunday-monday -星期六 –