的Lua GSUB正則表達式來替換字符

Question

我想修改我的網址是乾淨和友好的多occurances通過去除特定字符

local function fix_url(str) 
return str:gsub("[+/=]", {["+"] = "+", ["/"] = "/", ["="] = "="}) --Needs some regex to remove multiple occurances of characters 
end 
url = "///index.php????page====about&&&lol===you" 
output = fix_url(url) 

出現了多次，我想什麼來實現輸出爲這樣的：

"/index.php?page=about&lol=you" 

但是，相反我的輸出是這樣的：

"///index.php????page====about&&&lol===you" 

是GSUB日我應該這樣做嗎？

Answer 1

我不明白如何與一個調用gsub做到這一點。

url = "///index.php????page====about&&&lol===you" 

function fix_url(s,C) 
    for c in C:gmatch(".") do 
     s=s:gsub(c.."+",c) 
    end 
    return s 
end 

print(fix_url(url,"+/=&?")) 

Answer 2

這裏是一個可能的解決方案（與任何字符類你喜歡的替換％P）：

local 
function fold(s) 
    local ans = '' 
    for s in s:gmatch '.' do 
    if s ~= ans:sub(-1) then ans = ans .. s end 
    end 
    return ans 
end 

local 
function fix_url(s) 
    return s:gsub('%p+',fold) --remove multiple same characters 
end 

url = '///index.php????page====about&&&lol===you' 
output = fix_url(url) 

print(output)