如果我理解正確你的問題,你可以完成你做一些SELF JOINS
尋找什麼。
CREATE TABLE #aa(
ID INT,
QuestionCode NVARCHAR(100),
SomeNumber BIGINT,
DateColumn DATETIME,
NullColumn1 INT,
NullColumn2 INT,
Answer varchar (100),
AnswerLetter char
)
INSERT #aa (ID,QuestionCode,SomeNumber,DateColumn,Answer,AnswerLetter)
VALUES
(331,'QUIZ0000000062',919652503596,'2017-07-10 18:54:33.217','Falciform ligament','A'),
(332,'QUIZ0000000062',919652503596,'2017-07-10 18:54:33.217','Coronary ligament','B'),
(333,'QUIZ0000000062',919652503596,'2017-07-10 18:54:33.217','Mesentery of the lesser sac','C'),
(334,'QUIZ0000000062',919652503596,'2017-07-10 18:54:33.217','Ligamentum teres','D')
SELECT q.QuestionCode,a.Answer 'A',b.Answer 'B',c.Answer 'C',d.Answer 'D'
FROM #aa q
JOIN #aa a ON q.AnswerLetter = a.AnswerLetter AND a.AnswerLetter = 'A'
JOIN #aa b ON q.AnswerLetter = a.AnswerLetter AND b.AnswerLetter = 'B'
JOIN #aa c ON q.AnswerLetter = a.AnswerLetter AND c.AnswerLetter = 'C'
JOIN #aa d ON q.AnswerLetter = a.AnswerLetter AND d.AnswerLetter = 'D'
DROP TABLE #aa
結果:
+---------------+--------------------+-------------------+-----------------------------+------------------+
| QuestionCode | A | B | C | D |
+---------------+--------------------+-------------------+-----------------------------+------------------+
|QUIZ0000000062 | Falciform ligament | Coronary ligament | Mesentery of the lesser sac | Ligamentum teres |
+---------------+--------------------+-------------------+-----------------------------+------------------+
會不會有永遠是四個選項(通過d A),或者你可以有一些更復雜的問題......說有更多的選擇匹配的問題。 –