我如何獲得我的外部/ IP？

Question

可能重複：
How to get ip address of the device?

下面是如何我試圖讓外部IP片段。但是，它不返回任何東西......

public String getIpAddress() { 

    try { 
      HttpClient httpclient = new DefaultHttpClient(); 
      HttpGet httpget = new HttpGet("http://www.whatismyip.com/?404"); 
      // HttpGet httpget = new HttpGet("http://whatismyip.com.au/"); 
      // HttpGet httpget = new HttpGet("http://www.whatismyip.org/"); 
      HttpResponse response; 

      response = httpclient.execute(httpget); 

      //Log.i("externalip",response.getStatusLine().toString()); 

      HttpEntity entity = response.getEntity(); 
      entity.getContentLength(); 
      str = EntityUtils.toString(entity); 
    } 
    catch (Exception e) 
    { 
    } 
    return str; 

} 

Answer 1

public String getIpAddress() { 
String ip; 
    try { 
     HttpClient httpclient = new DefaultHttpClient(); 
     HttpGet httpget = new HttpGet("http://ip2country.sourceforge.net/ip2c.php?format=JSON"); 
     // HttpGet httpget = new HttpGet("http://whatismyip.com.au/"); 
     // HttpGet httpget = new HttpGet("http://www.whatismyip.org/"); 
     HttpResponse response; 

     response = httpclient.execute(httpget); 
     //Log.i("externalip",response.getStatusLine().toString()); 

     HttpEntity entity = response.getEntity(); 
     entity.getContentLength(); 
     str = EntityUtils.toString(entity); 
     Toast.makeText(getApplicationContext(), str, Toast.LENGTH_LONG).show(); 
     JSONObject json_data = new JSONObject(str); 
     ip = json_data.getString("ip"); 
     Toast.makeText(getApplicationContext(), ip, Toast.LENGTH_LONG).show(); 
    } 
    catch (Exception e){...} 

    return ip; 
} 

OR

UPDATE 2015年2月

WhatIsMyIp現在公開您可以使用的developer API。

Answer 2

，你可以看看這裏 http://code.google.com/p/external-ip/source/browse/src/org/kost/externalip/ExternalIP.java

和這裏 External ip address in android programatically