我面臨間歇性應用程序流問題。 在這裏,我有一個登錄屏幕,我可以第一次登錄。但是當我註銷和/或重新登錄時,我無法進一步遍歷。作爲解決方法,我需要卸載我的應用程序並重新安裝,並且流程正常。Android:Intermitent應用程序流問題
任何人都可以請指導我在可能的問題。
LoginActivity.java
GetWebServiceManager passwordExpiryWSManager = new GetWebServiceManager();
//to check network connectivity (data connection/Wi-Fi)
ConnectivityManager connectionManager = (ConnectivityManager) getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo networkInformation = connectionManager.getActiveNetworkInfo();
if (networkInformation != null && networkInformation.isConnected() == true) {
try {
// passwordExpiryString = passwordExpiryWSManager.execute("http://172.25.164.143:8088/api/Login/GetExpiredPassword/?lContactKey=" + username.getText().toString()).get();
passwordExpiryString = passwordExpiryWSManager.execute(AppConstants.URL + "/Login/GetExpiredPassword/?lContactKey=" + username.getText().toString()).get();
jsonObjectPassExpiry = new JSONObject(passwordExpiryString);
jsonArrayPassExpiry = jsonObjectPassExpiry.getJSONArray("LstLoginDetail");
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (ExecutionException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
/*
* Converting JSON string response from Webservice into Java Object
* */
if (jsonArrayPassExpiry != null) {
Gson gson = new Gson();
LoginTO[] loginExpTO = gson.fromJson(jsonArrayPassExpiry.toString(), LoginTO[].class);
loginListPassExpiry = Arrays.asList(loginExpTO);
intent = getIntent();
if (loginListPassExpiry.get(0).getlSuccess() == 1) {
intent.setClass(getApplicationContext(), PortfolioSummaryFragmentActivity.class);
// intent.putExtra("sToken", loginList.get(0).getsToken());
startActivity(intent);
} else {
intent.setClass(getApplicationContext(), PasswordExpiryActivity.class);
// intent.putExtra("sToken", loginList.get(0).getsToken());
startActivity(intent);
}
} else {
Toast.makeText(getApplicationContext(), "Service is not responding. Please try again later!!", Toast.LENGTH_SHORT).show();
}
} else {
Toast.makeText(getApplicationContext(), "Network connection unavailable. Please check your data plan or Wi-Fi connection!!", Toast.LENGTH_SHORT).show();
}
Logout.java
public class LogoutActivity extends Activity {
private TextView successResponse;
private Intent intent;
private Button btnLLogin;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.logout_success);
successResponse = (TextView) findViewById(R.id.txtvwLSuccessMessage);
btnLLogin = (Button) findViewById(R.id.btnLLogin);
intent = getIntent();
successResponse.setText(intent.getStringExtra("successResponse"));
}
public void Login(View v) {
btnLLogin.setTextColor(getResources().getColor(R.color.black));
intent = new Intent(this, LoginActivity.class);
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
startActivity(intent);
}
@Override
public void onBackPressed() {
finish();
}
}
您能解釋「我無法進一步遍歷」嗎?您的意思是說startActivity()方法不會執行......或者他們做但不工作。你也需要自由地添加一些Log.d(「我在這裏XXX」);語句來幫助您調試這些情況。 – robnick
你在哪裏打電話登錄(查看v)在你的代碼? –
請做一些家庭工作與http://www.peachpit.com/articles/article.aspx?p=1874864 –