如何將列表操作爲字符串並在單獨的行中打印

Question

我試圖用下面的代碼導出4列。最後一列組織是List。

String appname = "abc"; 
    String path = "//home/exportfile//"; 
    String filename = path + "ApplicationExport-" + appname + ".txt"; 
    String ret = "false"; 

    QueryOptions ops = new QueryOptions(); 
    Filter[] filters = new Filter[1]; 
    filters[0] = Filter.eq("application.name", appname); 
    ops.add(filters); 

    List props = new ArrayList(); 
    props.add("identity.name"); 

    // Do search 
    Iterator it = context.search(Link.class, ops, props); 

    // Build file and export header row 
    BufferedWriter out = new BufferedWriter(new FileWriter(filename)); 
    out.write("IdentityName,UserName,WorkforceID,Organization"); 
    out.newLine(); 

    // Iterate Search Results 
    if (it != null) { 
     while (it.hasNext()) { 

      // Get link and create object 
      Object[] record = it.next(); 
      String identityName = (String) record[0]; 
      Identity user = (Identity) context.getObject(Identity.class, identityName); 

      // Get Identity attributes for export 
      String workforceid = (String) user.getAttribute("workforceID"); 

      // Get application attributes for export 
      String userid = ""; 

      List links = user.getLinks(); 
      if (links != null) { 
       Iterator lit = links.iterator(); 
       while (lit.hasNext()) { 
        Link l = lit.next(); 
        String lname = l.getApplicationName(); 
        if (lname.equalsIgnoreCase(appname)) { 
         userid = (String) l.getAttribute("User Name"); 
         List organizations = l.getAttribute("Organization"); 

         StringBuilder sb = new StringBuilder(); 
         String listItemsSeparator = ","; 

         for (Object organization : organizations) { 
          sb.append(organization.toString()); 
          sb.append(listItemsSeparator); 
         } 

         org = sb.toString().trim(); 

        } 
       } 
      } 

      // Output file 
      out.write(identityName + "," + userid + "," + workforceid + "," + org); 
      out.newLine(); 
      out.flush(); 
     } 

     ret = "true"; 
    } 

    // Close file and return 
    out.close(); 
    return ret; 

上面的代碼的輸出將be.for例如：

IdentityName,UserName,WorkforceID,Organization 

dthomas,dthomas001,12345,Finance,HR 

我如何獲得在下面的方式輸出

IdentityName,UserName,WorkforceID,Organization 

dthomas,dthomas001,12345,Finance 

dthomas,dthomas001,12345,HR 

什麼，在哪裏我需要改變碼？

Answer 1

你必須一行寫入文件每個組織。因此，基本上，不要將用戶的所有組織連接到字符串構建器，並將輸出語句移到遍歷組織的for循環中。

但它很難提供一個工作的例子，因爲你是你，並不包括尚未編譯代碼...

---

您應該會稍微接近於解決方案：

if (links != null) { 
    Iterator lit = links.iterator(); 
    while (lit.hasNext()) { 
    Link l = lit.next(); 
    String lname = l.getApplicationName(); 
    if (lname.equalsIgnoreCase(appname)) { 
     userid = (String) l.getAttribute("User Name"); 
     List organizations = l.getAttribute("Organization"); 
     for (Object organization : organizations) { 
     // Output file 
     out.write(identityName + "," + userid + "," + workforceid + "," + organization); 
     out.newLine(); 
     out.flush(); 
     } 
    } 
    } 
} 

Answer 2

刪除此最內for塊和相關聯的變量：

StringBuilder sb = new StringBuilder(); 

for (Object organization : organizations) 
{ 
    sb.append(organization.toString()); 
    sb.append(listItemsSeparator); 
} 

org = sb.toString().trim(); 

移動的organizations外的if (it != null) {塊的聲明：

// Get application attributes for export 
String userid = ""; 
List organizations = null; 
List links = user.getLinks(); 

if (it != null) 
{ 
    Iterator lit = links.iterator(); 
    while (lit.hasNext()) 
    { 
     Link l = lit.next(); 
     String lname = l.getApplicationName(); 
     if (lname.equalsIgnoreCase(appname)) 
     { 
      userid = (String) l.getAttribute("User Name"); 
      organizations = l.getAttribute("Organization"); 

，然後改變該文件輸出代碼：

// Output file 
out.write(identityName + "," + userid + "," + workforceid + "," + org); 
out.newLine(); 

要這樣：

// Output file 
for (Object organization : organizations) 
{ 
    out.write(identityName + "," + userid + "," + workforceid + "," + organization.toString()); 
    out.newLine(); 
}