如果你要申請的PIVOT
功能,您將需要使用集合函數來得到結果,但你會也希望使用窗口功能,如row_number()
爲帳戶中的每個聯繫人生成唯一序列。
首先,你將查詢數據類似於:
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
見SQL Fiddle with Demo。這將創建一個新列具有唯一的序列:
| ACCOUNT | CONTACT | SEQ |
|---------|-----------|----------|
| 1 | 324324324 | contact1 |
| 1 | 674323234 | contact2 |
如果你有列的數量有限,那麼你可以硬編碼查詢:
select account,
contact1, contact2, contact3, contact4
from
(
select account, contact,
'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
pivot
(
max(contact)
for seq in (contact1, contact2, contact3, contact4)
) piv;
見SQL Fiddle with Demo
如果你有不明數量的列,那麼你將不得不使用動態SQL:
DECLARE @cols AS NVARCHAR(MAX),
@query AS NVARCHAR(MAX)
select @cols = STUFF((SELECT ',' + QUOTENAME(seq)
from
(
select 'contact'
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) d
group by seq
order by seq
FOR XML PATH(''), TYPE
).value('.', 'NVARCHAR(MAX)')
,1,1,'')
set @query = 'SELECT account, ' + @cols + '
from
(
select account, contact,
''contact''
+ cast(row_number() over(partition by account
order by contact) as varchar(10)) seq
from yourtable
) x
pivot
(
max(contact)
for seq in (' + @cols + ')
) p '
execute sp_executesql @query;
見SQL Fiddle with Demo。這兩種會給你的結果:
| ACCOUNT | CONTACT1 | CONTACT2 | CONTACT3 | CONTACT4 |
|---------|-----------|-----------|-----------|-----------|
| 1 | 324324324 | 674323234 | (null) | (null) |
| 2 | 433243443 | 833343432 | (null) | (null) |
| 3 | 787655455 | (null) | (null) | (null) |
| 4 | 455435435 | 754327545 | (null) | (null) |
| 5 | 432432432 | 432433242 | 432455553 | 543544355 |