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這裏是我的情況：覆蓋數組的前n個元素？
a = ["","","","","","","","","",""] #10 elements. Need not always be blank.
b = ["a","b","c","d"]
我想修改a使得a第一n元件用的b的元素，其中n = b.size()代替：
a = ["a","b","c","d","","","","","",""]
那麼，有沒有一些簡單的像a.replace(b)減去截斷？
另一種方法是將a.size() - b.size()元素數加到b。