如何將字符串分割成組，匹配paranthisisbin在C＃

Question

有什麼辦法來分割下文提到的字符串轉換成使用正則表達式組[用括號分組]

Input: "[Id]=@id,{buyerid}<>@id,[userid]>@userid,{custid}=@custid,status>1" 

條件：

1.Need到在單獨的csvs和不帶圓括號的表達式中分隔類似的括號表達式。括號將只在左側operator.Allowed運營商是=，>，<>，<，！=

[ anytext    ] = @anytetx 
{ anytext    } =@anytetext 
anytext withot parathis =@anytetx 

2.運營商的左側，始終存在一些純文本沒有任何括號專包機或者沒有括號的情況下，但運營商的右側有可以實現文字，如：@accountid，「ACCOUNTID」，並於1983年1月1日＃＃和布爾值true或false 輸出數字和日期：

1. "[Id]=@id,[userid]>@userid" 

2. "{buyerid}<>@id,{custid}=@custid" 

3. "status>1" 

Answer 1

當然，這裏是你如何在Python中做到這一點。

1.py：

import re 

txt='[Id]=@id,{buyerid}<>@id,[userid]>@userid,{custid}=@custid,status>1' 

re1='(.*?),' # Command Seperated Values 1 
re2='.*?' # Non-greedy match on filler 
re3='.*?,' # Uninteresting: csv 
re4='.*?' # Non-greedy match on filler 
re5='.*?,' # Uninteresting: csv 
re6='.*?' # Non-greedy match on filler 
re7='(.*?),' # Command Seperated Values 2 

rg = re.compile(re1+re2+re3+re4+re5+re6+re7,re.IGNORECASE|re.DOTALL) 
m = rg.search(txt) 
if m: 
    csv1=m.group(1) 
    csv2=m.group(2) 
    print "("+csv1+")"+"("+csv2+")"+"\n" 

2.py：

import re 

txt='[Id]=@id,{buyerid}<>@id,[userid]>@userid,{custid}=@custid,status>1' 

re1='.*?' # Non-greedy match on filler 
re2='.*?,' # Uninteresting: csv 
re3='(.*?),' # Command Seperated Values 1 
re4='.*?' # Non-greedy match on filler 
re5='(\\{custid\\}=@custid)' # Command Seperated Values 2 

rg = re.compile(re1+re2+re3+re4+re5,re.IGNORECASE|re.DOTALL) 
m = rg.search(txt) 
if m: 
    csv1=m.group(1) 
    csv2=m.group(2) 
    print "("+csv1+")"+"("+csv2+")"+"\n" 

3.py：

import re 

txt='[Id]=@id,{buyerid}<>@id,[userid]>@userid,{custid}=@custid,status>1' 

re1='.*?' # Non-greedy match on filler 
re2='(status)' # Word 1 
re3='(>)' # Any Single Character 1 
re4='(\\d+)' # Integer Number 1 

rg = re.compile(re1+re2+re3+re4,re.IGNORECASE|re.DOTALL) 
m = rg.search(txt) 
if m: 
    word1=m.group(1) 
    c1=m.group(2) 
    int1=m.group(3) 
    print "("+word1+")"+"("+c1+")"+"("+int1+")"+"\n"