0
的結果我有一個JSON結構是這樣的:如何使用OPENJSON在子OPENJSON
Declare @layout NVARCHAR(MAX) = N'
{
"Sections": [
{
"SectionName":"Section1",
"SectionOrder":1,
"Fields":[
{
"FieldName":"Field1",
"FieldData":"Data1"
},
{
"FieldName":"Field2",
"FieldData":"Data2"
}
]
},
{
"SectionName":"Section2",
"SectionOrder":2,
"Fields":[
{
"FieldName":"Field3",
"FieldData":"Data3"
},
{
"FieldName":"Field4",
"FieldData":"Data4"
}
]
}
]
}
'
如何查詢到Sections.Fields.FieldName =「字段3」的相同呢?
select *
from OPENJSON(@layout,'$.Sections')
WITH (
SectionName nvarchar(MAX) '$.SectionName',
SectionOrder nvarchar(MAX) '$.SectionOrder',
Fields nvarchar(MAX) '$.Fields' as JSON
)
這是據我所知,我不能再下去或它不會返回任何結果。
該文檔是一件神奇的事情。應該首先諮詢。 – dfundako