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我有兩個殭屍對象,一個是Grunt
,另一個是Runner
。多種類型的繪製表
我Grunt.lua
文件:
function InitGrunt()
grunt = {}
grunt.x = 0
grunt.y = 0
grunt.speed = 120
grunt.hitBox = (sprites.grunt:getHeight() + sprites.grunt:getWidth())/2
grunt.hit = false
gruntDefCD = 2
gruntCD = gruntDefCD
gruntMinCD = 0.4
gruntTimer = gruntCD
gruntTimerDecr = 0.8
end
function SpawnGrunt()
local side = math.random(1, 4)
--randomize spawn position
table.insert(zombies, grunt)
end
和我Runner.lua
:
function InitRunner()
runner = {}
runner.x = 0
runner.y = 0
runner.speed = 240
runner.hitBox = (sprites.runner:getWidth() + sprites.runner:getHeight())/2
runner.hit = false
runnerDefCD = 4
runnerCD = runnerDefCD
runnerMinCD = 2
runnerTimer = runnerCD
runnerTimerDecr = 0.95
end
function SpawnRunner()
local side = math.random(1, 4)
--randomize spawn position
table.insert(zombies, runner)
end
所以zombie
表將有grunt
S和runner
秒。如何在Draw()
中打印它們?
我可以得出一個有:
function DrawGrunts()
for i, z in ipairs(zombies) do
love.graphics.draw(sprites.grunt, z.x, z.y, PlayerZombieAngle(z), nil, nil, sprites.grunt:getWidth()/2, sprites.grunt:getHeight()/2)
end
end
但我怎麼在一個函數繪製他們兩個,理想?