添加確認彈出

Question

我有這樣的代碼行：

$action = "window.location = 'fruit_list.php.php?do=delete&id={$fruitdata['id']}"; 
echo '<a style="cursor: pointer" onclick="javascript:' . $action . '">Delete</a>';?> 

有沒有辦法添加以下代碼，以使確認框彈出時鏈接點擊？

onclick="return confirm('are you sure?')" 

Answer 1

你並不需要添加回的onclick，只是

<a href='#' onclick='confirm("Are you sure?")'> Click </a>

http://jsfiddle.net/PFKFq/1/

Answer 2

$action = "if(window.event) event=window.event; event.preventDefault();if (confirm('Are you sure?')){window.location = 'fruit_list.php.php?do=delete&id={$fruitdata['id']} }"; 
echo '<a style="cursor: pointer" onclick="javascript:' . $action . '">Delete</a>';?> 

Answer 3

爲什麼你不使用href？

<?php 
$link = "fruit_list.php?do=delete&id={$fruitdata['id']}"; 
echo "<a href='{$link}' onclick='return confirm(\"Delete ?\");'>Delete</a>";