PHP管道，爲什麼對象被克隆？

Question

我正在看一些php代碼，並偶然發現了一個管道腳本。在向管道中添加內容的方法中：

public function pipe(callable $stage) 
{ 
    $pipeline = clone $this; 
    $pipeline->stages[] = $stage; 
    return $pipeline; 
} 

該對象正在克隆並返回。 有人可以解釋我這種方法的優點， 會不會在下面的代碼返回相同的結果？

public function pipe(callable $stage) 
{  
    $this->stages[] = $stage; 
    return $this; 
} 

Answer 1

不，它不會返回相同的。 Clone創建對象的副本，這有時是所需的行爲。

class WithoutClone { 
    public $var = 5; 

    public function pipe(callable $stage) 
    {  
     $this->stages[] = $stage; 
     return $this; 
    } 
} 

$obj = new WithoutClone(); 
$pipe = $obj->pipe(...); 
$obj->var = 10; 
echo $pipe->var; // Will echo 10, since $pipe and $obj are the same object 
       // (just another variable-name, but referencing to the same instance); 

// ---- 

class Withlone { 
    public $var = 5; 

    public function pipe(callable $stage) 
    {  
     $pipeline = clone $this; 
     $pipeline->stages[] = $stage; 
     return $pipeline; 
    } 
} 

$obj = new WithClone(); 
$pipe = $obj->pipe(...); 
$obj->var = 10; 
echo $pipe->var; // Will echo 5, since pipe is a clone (different object);