呼應一定數值時出數組等於你的函數

Question

我有了這樣的數組：

$autos[] = array(
     "auto" => "Audi A6", 
     "Max snelheid" => "240 km/h", 
     "Verbruik" => "1 op 12"); 

$autos[] = array(
     "auto" => "Porsche 911", 
     "Max snelheid" => "290 km/h", 
     "Verbruik" => "1 op 8"); 

和下面我用Echo的這一個foreach。

foreach ($autos as $cars => $arr){ 
    echo '<tr>'; 
     foreach($arr as $test => $data){ 
      echo '<td>'.$data.'</td>'; 
    } 
    echo '</tr>'; 
} 

我怎麼能呼應的東西時，這個值是"Verbruik" => "1 op 11" 如果第2個數字是高於11我要呼應「這是正確的」。

這樣的例子是：

$autos[] = array(
    "auto" => "Fiat Panda", 
    "Max snelheid" => "140 km/h", 
    "Verbruik" => "1 op 11"); 

所以當我有上面的代碼。我怎麼回聲「這是正確的」？

Answer 1

使用explode（）函數將字符串「1 op 12」分解爲2個數字的數組，然後檢查第二個數字是否大於11或任何你想要的。

foreach ($autos as $cars => $arr){ 
    echo '<tr>'; 
     foreach($arr as $test => $data){    
      echo '<td>'.$data." "; 
      if($test == "Verbruik"){ 
       $temp = explode(" op ",$data); 
       if($temp[1] > 11){ 
        echo "correct "; // do whatever you want 
       } 
      } 
      echo '</td>'; 
    } 
    echo '</tr>'; 
} 

Answer 2

試試這個：

foreach ($autos as $cars => $arr){ 
    echo '<tr>'; 
     foreach($arr as $test => $data){ 
      $numbers = explode(" op ", $data); 
      if($test == 'Verbruik'){ 

       if((int) $numbers[1] >= 11) 

        echo '<td>'.$data." , That's correct!</td>"; 
      } 

      else 
       echo '<td>'.$data.'</td>'; 
    } 
    echo '</tr>'; 
}