結合多個MySQL查詢到一個

IM學習的MySQL命令，並結合多個查詢的方法，所以爲了獲得這個目標，現在我需要把這些查詢組合：結合多個MySQL查詢到一個

list($TotalVisitsToday) = $db->sql_fetchrow($db->sql_query("SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE `date_time` between '$yesterday' and '$today' ")); 
    list($TotalVisitsYesterday) = $db->sql_fetchrow($db->sql_query("SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE `date_time` between '$yesterday_1' and '$yesterday' ")); 

    list($TotalPVisitsToday) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE `date_time` between '$yesterday' and '$today'")); 
    list($TotalPVisitsYesterday) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE `date_time` between '$yesterday_1' and '$yesterday'")); 

    list($TotalCrawlers) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE hostname LIKE '%crawl%' "));

我對如何不知道混合上面的行！

來源

2010-10-03 Mac Taylor

你可能形成的SQL語句組成工會，像...

SELECT COUNT(DISTINCT ip_address) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday' and '$today' 
UNION 
SELECT COUNT(DISTINCT ip_address) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday_1' and '$yesterday' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday' and '$today' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday_1' and '$yesterday' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE hostname LIKE '%crawl%'

我不能說我會建議這一點，雖然。結果集不同行意味着不同的東西，從長遠來看可能會證明麻煩。

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2010-10-03 09:16:27

我試過聯盟之前，你建議這個答案，但結果是零和不起作用 – 2010-10-05 18:19:56

我不知道你的最終目標，但如果你只是想在一個查詢，你可以做這樣的：

SELECT 
(SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE 'date_time' between '$yesterday' and '$today') COUNT1, 
(SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE 'date_time' between '$yesterday_1' and  '$yesterday') COUNT2, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE 'date_time' between '$yesterday' and '$today') COUNT3, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE 'date_time' between '$yesterday_1' and '$yesterday') COUNT4, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE hostname LIKE '%crawl%') COUNT5

（你可以在MySQL省略FROM caluse）

來源

2010-10-03 09:26:33

你的答案很酷，我試過了，但它沒有工作，你確定的語法嗎？ – 2010-10-05 18:19:18

是的，語法是正確的，你會得到什麼錯誤？ – 2010-10-06 02:08:13

另外，它是MySQL還是PHP相關？你確定變量佔位符被你的PHP腳本中的值正確替換嗎？不幸的是，由於我是一名ASP.NET開發人員，因此我無法幫助您，但語法對MySQL確實有效（實際上很簡單）。嘗試從MySQL客戶端（如MySQL命令行）運行查詢以確保其正常工作。 – 2010-10-06 02:24:25

結合多個MySQL查詢到一個

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