無法從xml文件獲取值

當我嘗試獲取值時，它似乎不起作用。 xml文件包含多個同一節點<post>，我認爲你可以像數組一樣調用特定的節點，但這似乎不起作用。下面我已經包含了代碼。無法從xml文件獲取值

文件獲取XML值：包含上述文件中

<?php 

if(file_exists('settings.xml')){ 
    $settings = simplexml_load_file('settings.xml'); 

    $site_title = $settings->title; 
    $site_name = $settings->title; 
    $site_stylesheet = "css/main.css"; 

    $theme_folder = "themes/".$settings->theme; 
    if(file_exists('posts.xml')){ 
     $posts = simplexml_load_file('posts.xml'); 

     $post = $posts->post[$_GET['post']]; 

     $post_title = $post->title; 
     $post_content = $post->content; 
     $post_author = $post->author; 


     include($theme_folder."/header.php"); 
     include($theme_folder."/post.php"); 
     include($theme_folder."/footer.php"); 
    } else { 
     exit("File \"posts.xml\" does not exist!"); 
    } 
} else { 
    exit("File \"settings.xml\" does not exist!"); 
} 

?>

文件，並使用該XML傳遞給變量：

<article> 
    <h1><?php echo $post_title ?></h1> 
    <?php echo $post_content ?> 
    <p><?php echo $post_author ?></p> 
</article>

XML文件：

<?xml version="1.0" encoding="utf-8"?> 
<posts> 
    <post> 
     <title>Hello World</title> 
     <author>tacticalsk8er</author> 
     <content>Hello world this is my blogging site</content> 
    </post> 
    <post> 
     <title>Hello Again</title> 
     <author>Nick Peterson</author> 
     <content><![CDATA[Hello Again world this is another test for my <b>blogging site</b>]]></content> 
    </post> 
</posts>

來源

2013-11-15 tacticalsk8er

當然，您可以訪問節點simplexml'array-style'：

$post = $xml->post[1]; // select second node 
echo $post->title;

$xml表示根節點<posts>，$xml->post選擇posts/post。

看到它的工作：http://3v4l.org/KOiv2

看到手冊： '？post.php中後期= 0' http://www.php.net/manual/en/simplexml.examples-basic.php

來源

2013-11-15 23:41:58 michi

爲什麼然後當我通過像一個URL它不工作？ – tacticalsk8er

@ tacticalsk8er：嘗試'$ id = intval（$ _ GET ['post']）; $ post = $ xml-> post [$ id];' – michi

工作正常！是因爲當你傳遞'$ _GET'時，你實際上傳遞了一個字符串？ – tacticalsk8er

無法從xml文件獲取值

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