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我在JPA是新的,我都不再按照我的項目單位:JPA persit創造了許多新的現有實體到一個關係
動物實體:
package com.shop.model;
import java.io.Serializable;
import javax.persistence.*;
@Entity
@NamedQueries({
@NamedQuery(name="Animal.findAll", query="SELECT a FROM Animal a"),
@NamedQuery(name="Animal.findAllByTypeId", query="SELECT a FROM Animal a WHERE a.type.id = :id"),
})
public class Animal implements Serializable {
private static final long serialVersionUID = 1L;
public static String SMALL = "small";
public static String MEDIUM = "medium";
public static String LARGE = "large";
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int id;
@Lob
private String description;
private String name;
private String size;
@ManyToOne(cascade=CascadeType.PERSIST)
private Type type;
public Animal() {
}
public int getId() {
return this.id;
}
public void setId(int id) {
this.id = id;
}
public String getDescription() {
return this.description;
}
public void setDescription(String description) {
this.description = description;
}
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
public String getSize() {
return this.size;
}
public void setSize(String size) {
this.size = size;
}
public Type getType() {
return this.type;
}
public void setType(Type type) {
this.type = type;
}
}
類型的實體:
package com.shop.model;
import java.io.Serializable;
import javax.persistence.*;
import java.sql.Timestamp;
import java.util.List;
@Entity
@NamedQueries({
@NamedQuery(name="Type.findAll", query="SELECT t FROM Type t"),
})
public class Type implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue(strategy=GenerationType.IDENTITY)
private int id;
private Timestamp created;
private String name;
@OneToMany(mappedBy="type", cascade=CascadeType.PERSIST)
private List<Animal> animals;
public Type() {
}
public int getId() {
return this.id;
}
public void setId(int id) {
this.id = id;
}
public Timestamp getCreated() {
return this.created;
}
public void setCreated(Timestamp created) {
this.created = created;
}
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
public List<Animal> getAnimals() {
return this.animals;
}
public void setAnimals(List<Animal> animals) {
this.animals = animals;
}
public Animal addAnimal(Animal animal) {
getAnimals().add(animal);
animal.setType(this);
return animal;
}
public Animal removeAnimal(Animal animal) {
getAnimals().remove(animal);
animal.setType(null);
return animal;
}
}
我創建新的類型爲:
Type type = new Type();
type.setName("Some new animal type");
this.entityManager.getTransaction().begin();
this.entityManager.persit(type);
this.entityManager.getTransaction().commit();
int lastInsertId = type.getId(); // wotks great!
但是,當我嘗試使用現有類型產生新動物並且JPA創建一個新類型時,會創建 。這裏是例子
Animal animal = new Animal();
Type type = this.entityManager.getReference(Type.class, 9);
animal.setName(name);
animal.setDescription(description);
animal.setSize(size);
animal.setType(type);
this.entityManager.getTransaction().begin();
this.entityManager.persit(animal);
this.entityManager.getTransaction().commit();
int lastId = animal.getId(); // works great !
它工作正常(一個新的動物被創造),但它也帶來了新的類型,這是問題。我也試過用find(Object object,int id)方法,但它仍然創建一個新的Type。
我試過合併方法而不是persit,它工作正常!但getId返回的值爲。
我需要使用和現有的類型創建一個新的動物,也得到最後一個ID。那可能嗎?
謝謝阿修羅! – afym