如何在不使用限制函數的情況下計算MySQL子查詢中最重複的值

Question

我想計算表中最重複的值，但它是在子查詢中完成的，而我的SQLyog不支持該類型的查詢，下面是我的查詢：

SELECT `band`.`band_id`,`member_id`,`member_name`,`contact_no` 
FROM seasons 
INNER JOIN programs_recorded ON programs_recorded.season_id=seasons.season_id 
INNER JOIN programs ON programs_recorded.program_id=programs.program_id 
INNER JOIN songs_performed ON songs_performed.program_id=programs.program_id 
INNER JOIN songs ON songs.song_id=songs_performed.song_id 
INNER JOIN `band` ON `band`.`song_id`=`songs`.`song_id` 
INNER JOIN `band_member` ON `band_member`.`band_id`=`band`.`band_id` 
WHERE `band`.`song_id` = ANY (SELECT `songs_performed`.`song_id` 
           FROM `songs_performed` 
           GROUP BY `song_id` 
           HAVING COUNT(`s_id`)>3) 
GROUP BY `member_id` ; 

正如你可以在上面看到我寫COUNT(s_id)>3這是不通用的，一個解決方案是，我通過和限制使用GROUP BY函數與順序沿着但SQLyog的給出錯誤說它在這個版本不支持。

Answer 1

無論如何，有什麼不對這樣的事情...

SELECT DISTINCT b.band_id 
       , member_id 
       , member_name 
       , contact_no 
      FROM seasons ss 
      JOIN programs_recorded pr 
      ON pr.season_id = ss.season_id 
      JOIN programs p 
      ON pr.program_id = p.program_id 
      JOIN songs_performed sp 
      ON sp.program_id = p.program_id 
      JOIN songs s 
      ON s.song_id = sp.song_id 
      JOIN band b 
      ON b.song_id = s.song_id 
      JOIN band_member bm 
      ON bm.band_id = b.band_id 
      JOIN 
       (SELECT sp.song_id 
        FROM songs_performed sp 
       GROUP 
        BY song_id 
       HAVING COUNT(s_id) > 3 
      ) x 
      ON x.song_id = b.song_id; 

？