我想顯示多個圖像從一個jsp頁面的servlet在我的旋轉木馬,但我只顯示第一個圖像。我想知道如何顯示所有結果的Sql query.The servlet代碼是顯示來自servlet的多個圖像
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
//response.setContentType("image/jpg");
HttpSession myses = request.getSession(true);
String imageid = request.getParameter("id");
//System.out.println("In servlet"+imageid);
ServletOutputStream o;
try {
Class.forName(driverName);
con = DriverManager.getConnection(url,userName,password);
String sql = "select mid from carousel_two where cid= '"+imageid+"'";
PreparedStatement stmt = con.prepareStatement(sql);
ResultSet rs = stmt.executeQuery();
myses.setAttribute("lis",rs);
byte[] obj = new byte[1434295];
byte[] sample = null;
int srcPos = 0;
//int i=0;
//String encoded =new String();
o = response.getOutputStream();
java.util.List<String> strings = new ArrayList<String>();
//StringJoiner joiner = new StringJoiner(",");
if(rs!=null) {
while(rs.next()) {
String sql1 = "select img from carousel_two where mid= '"+rs.getInt("mid")+"'";
PreparedStatement stmt1 = con.prepareStatement(sql1);
ResultSet rs1 = stmt1.executeQuery();
if(rs1!=null) {
while(rs1.next()){
//int id = rs.getInt(1);
//System.out.println("id = "+id);
sample = rs1.getBytes("img");
int length = sample.length;
System.arraycopy(sample, 0, obj,srcPos, length);
srcPos += length;
//System.out.println("Length required = " + srcPos);
//if(rs!=null) {
//System.out.println("mid"+rs.getInt("mid"));
//o.write(rs.getBytes("img"));
byte[] newArray = new byte[srcPos];
System.arraycopy(obj, 0, newArray, 0, srcPos);
response.setContentType("image/jpg");
// response.getOutputStream().write(newArray);
strings.add(DatatypeConverter.printBase64Binary(newArray));
//System.out.println(strings+"\n");
// encoded=DatatypeConverter.printBase64Binary(newArray);
}
}
//}
}
}
//int x=(encoded.split(";")).length;
// System.out.println("X"+x);
//encoded=String.join(",", strings1);
//encoded= String.join(",", strings);
String json = new Gson().toJson(strings);
response.setContentType("application/json");
response.setCharacterEncoding("UTF-8");
o.print(json);
o.flush();
}catch (Exception e) {
e.printStackTrace();
}
}
和JavaScript代碼是
function trigger(idx, state) {
document.getElementById('touchScroller').innerHTML=" ";
$.ajax({
type : "GET",
url : "Sampleimage1",
contentType :"application/json",
data:{id:idx},
success : function(data) {
var da=data;
//da=data.split(",");
//alert(typeof data);
//alert(da.length);
$.each(da,function(index,item){
alert(index);
$('#touchScroller').append('<img src="data:image/jpg;base64,' +item +'" />');
});
}
});
}
是新手到此所以任何幫助將不勝感激。
我正在將我的圖像轉換爲base64字符串,並將其存儲在ArrayList中strings.add(DatatypeConverter.printBase64Binary(newArray));並將該字符串轉換爲json。但是當我試圖在jsp中顯示圖像時,我得到了第一個圖像多次times.how糾正 –
Ramya
我在servlet中獲得的json是[「img1」,「img2」,「img3」]但我得到我的json jsp頁面是[「img1」,「img2」,「img3」] 0:img1, 1:img1, 2:img2所以當我嘗試在src中顯示img時,它顯示相同的圖像3次。就是它? – Ramya
我編輯了我的答案,你的內部循環有太多的隨機代碼。試試我發佈的那個。 – 11thdimension