如何在Java中使用XSLT 2.0和XSLT 3.0？

Question

我能夠在Java中使用XSLT 1.0如圖所示folllowing例如： -

copy.xml

<?xml version="1.0"?> 
<?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?> 
<catalog> 
    <book id="bk101"> 
     <author>Gambardella, Matthew</author> 
     <title>XML Developer's Guide</title> 
     <genre>Computer</genre> 
     <price>44.95</price> 
     <publish_date>2000-10-01</publish_date>   
     <description>An in-depth look at creating applications with 
XML.</description> 
    </book> 
    <book id="bk102"> 
     <author>Ralls, Kim</author> 
     <title>Midnight Rain</title> 
     <genre>Fantasy</genre> 
     <price>5.95</price> 
     <publish_date>2000-12-16</publish_date> 
     <description>A former architect battles corporate zombies, 
an evil sorceress, and her own childhood to become queen of the 
world.</description> 
    </book> 
    <book id="bk103"> 
     <author>Corets, Eva</author> 
     <title>Maeve Ascendant</title> 
     <genre>Fantasy</genre> 
     <price>5.95</price> 
     <publish_date>2000-11-17</publish_date> 
     <description>After the collapse of a nanotechnology society 
in England, the young survivors lay the foundation for a new 
society.</description> 
    </book> 
</catalog> 

copy.xsl

<?xml version="1.0"?> 
<xsl:stylesheet version="1.0" 
     xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > 

    <xsl:template match="/ | @* | node()"> 
    <xsl:copy> 
     <xsl:apply-templates select="@* | node()"/> 
    </xsl:copy> 
    </xsl:template> 

</xsl:stylesheet> 

Copy.java

package com.data.transform; 

import javax.xml.transform.Transformer; 
import javax.xml.transform.TransformerFactory; 
import javax.xml.transform.stream.StreamResult; 
import javax.xml.transform.stream.StreamSource; 

public class Copy { 

    public static void main(String args[]) throws Exception { 
     StreamSource source = new StreamSource("copy.xml"); 
     StreamSource stylesource = new StreamSource("copy.xsl"); 

     TransformerFactory factory = TransformerFactory.newInstance(); 
     Transformer transformer = factory.newTransformer(stylesource); 

     StreamResult result = new StreamResult(System.out); 
     transformer.transform(source, result); 
     } 
} 

輸出

<?xml version="1.0" encoding="UTF-8"?><?xml-stylesheet type="text/xsl" href="identityxfm.xsl"?><catalog> 
    <book id="bk101"> 
     <author>Gambardella, Matthew</author> 
     <title>XML Developer's Guide</title> 
     <genre>Computer</genre> 
     <price>44.95</price> 
     <publish_date>2000-10-01</publish_date>   
     <description>An in-depth look at creating applications with 
XML.</description> 
    </book> 
    <book id="bk102"> 
     <author>Ralls, Kim</author> 
     <title>Midnight Rain</title> 
     <genre>Fantasy</genre> 
     <price>5.95</price> 
     <publish_date>2000-12-16</publish_date> 
     <description>A former architect battles corporate zombies, 
an evil sorceress, and her own childhood to become queen of the 
world.</description> 
    </book> 
    <book id="bk103"> 
     <author>Corets, Eva</author> 
     <title>Maeve Ascendant</title> 
     <genre>Fantasy</genre> 
     <price>5.95</price> 
     <publish_date>2000-11-17</publish_date> 
     <description>After the collapse of a nanotechnology society 
in England, the young survivors lay the foundation for a new 
society.</description> 
    </book> 
</catalog> 

但是，現在我想在Java中使用包含在XSLT 2.0和XSLT 3.0幾件事情（如xsl:analyze-string，xsl:try等）。我怎樣才能做到這一點 ？

Answer 1

從Maven或者Sourceforge獲取Saxon 9 HE並將其放到類路徑中，然後在9.8或XSLT 3.0支持之前，使用Saxon 9.x支持XSLT 2.0（除流，高階函數，xsl:evaluate，模式感知，向後兼容性）與9.8。要獲得完整的XSLT 3.0支持，您需要to download Saxon 9 PE or EE from Saxonica，並將其與您購買的license或您在類路徑中請求的試用許可證放在一起。