2009-08-10 44 views
5

我有一個日期格式: 2009-08-10T16:03:03Z如何轉換XML日期格式,以可可

,我想轉換爲: @ 「MMM DD,HH:MM一個」

我在NSString中檢索xml格式。我試圖使用NSDateformatter: NSDateFormatter * df = [[NSDateFormatter alloc] init]; [df setDateFormat:@「MMM dd,HH:mm a」];

有什麼想法?

回答

6
NSString *yourXMLDate = @"2009-08-10T16:03:03Z" 
NSDateFormatter *inputFormatter = [[NSDateFormatter alloc] init]; 
[inputFormatter setDateFormat:@"yyyy-MM-dd'T'HH:mm:ss"]; 
NSDate *inputDate = [inputFormatter dateFromString:yourXMLDate]; 
NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init]; 
[outputFormatter setDateFormat:@"MMM dd, HH:mm a"]; 
NSString *outputDate = [outputFormatter stringFromDate:inputDate]; 

希望這有助於!

+0

這似乎不適用於我:2012-06-29 16:58:11.868 tabbed-test [36214:11903] yourXMLDate:2012-06-29T14:27:45Z 2012-06-29 16: 58:11.870 tabbed-test [36214:11903] InputDate:(null) – Setomidor 2012-06-29 14:58:35

2
NSDateFormatter *dateFormatter = [[[NSDateFormatter alloc] init] autorelease]; 
    [dateFormatter setDateFormat:@"E, d LLL yyyy HH:mm:ss Z"]; // Thu, 18 Jun 2010 04:48:09 -0700 
    NSDate *date = [dateFormatter dateFromString:self.currentDate]; 

    [item setObject:date forKey:@"date"]; 

    [items addObject:[item copy]]; 

這裏編輯下面的代碼

[dateFormatter setDateFormat:@"E, d LLL yyyy HH:mm:ss Z"]; // Thu, 18 Jun 2010 04:48:09 -0700 

您需要的格式。