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沒有人理解這個代碼的問題!它確實有效,但現在不行。我無法登錄到'個人資料頁'任何人都可以看到和發佈?連接登錄失敗PHP
<?php
session_start();
$error='';
if (isset($_POST['submit']))
{
if (empty($_POST['username']) || empty($_POST['password']))
{
$error = "Enter username & password";
}
else {
// Define $username and $password
$username=$_POST['username'];
$password=$_POST['password'];
$connection = mysql_connect("localhost", "root", "");
echo($connection);
$username = stripslashes($username);
$password = stripslashes($password);
$username = mysql_real_escape_string($username);
$password = mysql_real_escape_string($password);
$db = mysql_select_db("Windsor", $connection);
echo($db);
$sql = "SELECT * FROM PHP_Customer WHERE Email='$username' and Password='$password'";
echo($sql);
$result = mysql_query($sql);
$count=mysql_num_rows($result);
if ($count < 1)
{
$error = "Username or Password is incorrect";
}
else
{
$_SESSION['user_login'] = $username;
header('location: profile.php');
echo "hello world!"; // This is just for testing purposes
}
}
mysql_close($connection);
}
?>
正如我所說,它確實工作,無論出於何種原因它似乎不再。
你在這裏發現任何錯誤? –
請使用mysli_ *或PDO。因爲mysql_ *現在已被棄用。並嘗試寫入mysql錯誤代碼,以便您知道實際發生了什麼錯誤 –
無論如何,純粹是爲了調試目的,我嘗試了'\t \t \t echo($ sql);'如果我輸入了正確的值登錄細節,沒有顯示。然而,如果我輸入了不正確的詳細信息,則會打印查詢,如'SELECT * FROM PHP_Customer WHERE Email ='wrong'and Password ='wrong password'' –