我開始在linux上做pthread編程,並且在第一個程序中我完全搞不懂。下面是我正在運行的程序linux上的pthread執行
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
void *print_message_function(void *ptr);
int main(){
pthread_t thread1, thread2;
char *message1 = "Thread 1";
char *message2 = "Thread 2";
int iret1, iret2;
/* Create independent threads each of which will execute function */
iret1 = pthread_create(&thread1, NULL, print_message_function, (void*) message1);
iret2 = pthread_create(&thread2, NULL, print_message_function, (void*) message2);
/* Wait till threads are complete before main continues. Unless we */
/* wait we run the risk of executing an exit which will terminate */
/* the process and all threads before the threads have completed. */
pthread_join(thread1, NULL);
printf("amit");
pthread_join(thread2, NULL);
printf("Thread 1 returns: %d\n",iret1);
printf("Thread 2 returns: %d\n",iret2);
exit(0);
}
void *print_message_function(void *ptr){
char *message;
message = (char *) ptr;
printf("%s \n", message);
}
我想知道的第一件事是線程執行的順序是不連續的?
第二件事是我intelectally把印刷(「阿米特」);看到main在thread1終止時真的停止了,但是在輸出中我們可以看到的是printf語句首先被執行。整個過程的輸出是
線程1
線程2
amitThread 1返回:0
線程2返回:0
」是線程執行順序不是順序的「。這是正確的。如果你發現這裏有足夠的驚喜,請離開代碼並找到一本書的多線程編程。請一路閱讀本書。在編寫更多或更少的隨機代碼之前,您可能會尋找一個好的教程。這個問題相當複雜,而不是偶然探索的東西。 https://computing.llnl.gov/tutorials/pthreads/ – 2011-02-14 11:15:50
這真的是輸出?它輸出`ajay`而不是`amit`?你有什麼問題? – Falmarri 2011-02-14 11:16:37
對不起amit不ajay – 2011-02-14 11:17:30