爲什麼Socket可以在android模擬器上打開並連接到python服務器代碼並打開套接字!在其他手中當我在手機上運行相同的android代碼它不會運行。 didnt打開套接字..Any建議是什麼問題以及如何解決這樣的事情android mobile socket open
enter code here
import sys
from threading import Thread
import socket
import MySQLdb
allClients=[]
class Client(Thread):
def __init__(self,clientSocket):
Thread.__init__(self)
self.sockfd = clientSocket #socket client
self.name = ""
self.nickName = ""
def newClientConnect(self):
allClients.append(self.sockfd)
while True:
while True:
try:
rm= self.sockfd.recv(2048)
print rm
i=0
while (i<2):
if (rm) == row[i][0]:
reply="\n Welcome to our game %s: %s"%(rm,row[i][1])
self.sockfd.send(reply)
break
else:
i=i+1
if i==2:
reply="\n Error opaa ba2a"
self.sockfd.send(reply)
i=0
break
break
except ValueError:
self.sockfd.send("\n UNVAlied Comment ")
def run(self):
self.newClientConnect()
while True:
buff = self.sockfd.recv(2048)
if buff.strip() == 'quit':
self.sockfd.close()
break # Exit when break
else:
self.sendAll(buff)
#Main
if __name__ == "__main__":
#Server Connection to socket:
IP = '50.0.10.107'
PORT = 5807
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
print ("Server Started")
try:
serversocket.bind(('',54633))
except ValueError,e:
print e
serversocket.listen(5)
db= MySQLdb.connect(host= "localhost",
user="root",
passwd="newpassword",
db="new_schema")
x=db.cursor()
x.execute("SELECT * FROM lolo")
row = x.fetchall()
print "Connected to the Database"
while True:
(clientSocket, address) = serversocket.accept()
print 'New connection from ', address
ct = Client(clientSocket)
ct.start()
__all__ = ['allClients','Client']
的Python代碼和服務器代碼,它映射和按鈕,當點擊按鈕連接並開始在模擬器上
工作的偉大
呃學英語。我可以收集:他可以從模擬器打開一個套接字到他的python服務器,但不是在實際設備上 – 2011-05-17 22:37:30
是的。對不起,我的英語,我會盡力學習更好 – eoeo 2011-05-17 22:41:51
所以約翰在得到我的問題後,任何建議? – eoeo 2011-05-17 23:09:06