如何使用re.findall或re.search讓比賽沒有找到

Question

我有一個字符串，可以是：

test = 'Something Else (neW) other and another (nEw) with (nEw) ' 

我需要得到：

result = 'Something Else other and another with ' 

但最好的我「已經取得了迄今爲止是：

import re 
f = re.findall(ur'\(\s*[nN][eE][wW]\s*\)',test) 
for i in f: test = test.replace(i,'') 

如何使用findall獲得不匹配搜索模式的字符串的一部分？

Answer 1

re.sub：

>>> import re 
>>> test = 'Something Else (neW) other and another (nEw) with (nEw) ' 
>>> re.sub(r'\(\s*[nN][eE][wW]\s*\)','',test) 
'Something Else other and another with '