紅寶石字符串分區

Question

可能重複：
Split string into a list, but keeping the split pattern

"hello world, I am the universe".partition(/I am/) 
    #=> ["hello world, ", "I am", " the universe"] 

什麼是具有此輸出的紅寶石呢？請記住更復雜的字符串。

#=> ["hello world, ", "I am the universe"] 

複雜：

"hello world, I am the universe, I am the world".some_partitioning_function(/I am/) 
#=>["hello world, ", "I am the universe, ", "I am the world"] 

Answer 1

方法不存在嗎？添加您自己：

class String 
    def some_partitioning_function(delim_str) 
    split(delim_str).map.with_index do |str, i| 
     i > 0 ? delim_str + str : str 
    end 
    end 
end 

"hello world, I am the universe, I am the world".some_partitioning_function('I am') 

=> ["hello world, ", "I am the universe, ", "I am the world"] 

Answer 2

"hello world, I am the universe".split(/,\s(?=I\sam)/,2) 

難道真的是你要找的東西？

Answer 3

你說這不是the question的重複@pwned鏈接到，但它的種類是。你只需要稍微擺弄紅寶石。

s = "hello world, I am the universe, I am the world" # original string 
a = s.split(/(I am)/) 
#=> ["hello world, ", "I am", " the universe, ", "I am, " the world"] 

現在我們將使用上述鏈接SO問題中提出的解決方案。除了我們將跳過數組的第一個元素。

sliced = a[1..-1].each_slice(2).map(&:join) 
#=> ["I am the universe, ", "I am the world"] 

現在我們將它與我們遺漏的數組元素結合起來。

final = [a[0]] + sliced 
#=> ["hello world, ", "I am the universe, ", "I am the world"] 

扔到等的方法是：

class String 
    def split_and_include(words) 
    s = self.split(/(#{words})/) 
    [s[0]] + s[1..-1].each_slice(2).map(&:join) 
    end 
end 

"You all everybody. You all everybody.".split_and_include("all") 
#=> ["You ", "all everybody. You ", "all everybody."] 

我敢肯定有這樣做的更清潔的方式，我會在發現更簡單的方法更新了答案。

Answer 4

我想這個任務應該由正則表達式來解決，我的正則表達式是不那麼整齊，也許你以後可以修復它。

reg = /(.+?(?=I\sam))(I\sam.+?(?=I\sam)|I\sam.+$)/ 
str = "hello world, I am the universe, I am the world, I am the earth" 

str.scan(reg).flatten 
=> ["hello world, ", "I am the universe, ", "I am the world, ", "I am the earth"]