XPATH C＃返回一個XML節點與含有一定值

Question

我有，我想提取節點值的XML屬性：

      <oslc:creation rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/resources/com.ibm.rqm.planning.VersionedExecutionScript" /> 
          <oslc:resourceShape rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/shape/creation/com.ibm.rqm.planning.VersionedExecutionScript" /> 
          <oslc:resourceType rdf:resource="http://open-services.net/ns/qm#TestScript" /> 
         </oslc:CreationFactory> 
        </oslc:creationFactory> 
        <oslc:creationFactory> 
         <oslc:CreationFactory> 
          <dcterms:title>Default creation factory for TestResult</dcterms:title> 
          <oslc:creation rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/resources/com.ibm.rqm.execution.ExecutionResult" /> 
          <oslc:resourceShape rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/shape/creation/com.ibm.rqm.execution.ExecutionResult" /> 
          <oslc:resourceType rdf:resource="http://open-services.net/ns/qm#TestResult" /> 
         </oslc:CreationFactory> 
        </oslc:creationFactory> 
        <oslc:creationFactory> 
         <oslc:CreationFactory> 
          <dcterms:title>Default creation factory for TestCase</dcterms:title> 
          <oslc:creation rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/resources/com.ibm.rqm.planning.VersionedTestCase" /> 
          <oslc:resourceShape rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/shape/creation/com.ibm.rqm.planning.VersionedTestCase" /> 
          <oslc:resourceType rdf:resource="http://open-services.net/ns/qm#TestCase" /> 
         </oslc:CreationFactory> 
        </oslc:creationFactory> 
        <oslc:creationFactory> 
         <oslc:CreationFactory> 
          <dcterms:title>Default creation factory for TestExecutionRecord</dcterms:title> 
          <oslc:creation rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/resources/com.ibm.rqm.execution.TestcaseExecutionRecord" /> 
          <oslc:resourceShape rdf:resource="https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/shape/creation/com.ibm.rqm.execution.TestcaseExecutionRecord" /> 
          <oslc:resourceType rdf:resource="http://open-services.net/ns/qm#TestExecutionRecord" /> 
         </oslc:CreationFactory> 
        </oslc:creationFactory> 
        <oslc:creationFactory> 
         <oslc:CreationFactory> 
          <dcterms:title>Default creation factory for 
    </rdf:RDF> 

，我想獲得

<oslc:queryCapability>\<oslc:QueryCapability>\ attribute value of oslc:queryBase (which is :"https://timo-pcvirtual:9443/qm/oslc_qm/contexts/_yAh_8gCIEeS7hY-fywlluw/resources/com.ibm.rqm.planning.VersionedTestCase") 

我使用C＃，而此格式，但犯規返回屬性值...請幫助...

XPathNavigator nav = projectAreaContent.CreateNavigator(); 
    XmlNamespaceManager manager = new XmlNamespaceManager(nav.NameTable); 
    manager.AddNamespace("oslc", "http://open-services.net/ns/core#"); 
    manager.AddNamespace("rdf", "http://www.w3.org/1999/02/22-rdf-syntax-ns#"); 
    XPathNodeIterator iterator = nav.Select("//oslc:queryBase[contains(@rdf:resource,'VersionedTestCase')]", manager); 

Answer 1

使用LINQ to XML：

XNamespace oslc = "http://open-services.net/ns/core#"; 
XNamespace rdf = "http://www.w3.org/1999/02/22-rdf-syntax-ns#"; 

var list = XDocument.Parse(xmlstring) 
      .Descendants(oslc + "QueryCapability") 
      .Select(q => q.Element(oslc + "queryBase").Attribute(rdf + "resource").Value) 
      .ToList(); 

您可以使用XDocument.Load(filename)從文件中加載xml。