在sql中插入帶有max的列

Question

我不知道如何在max中插入列。

Select id,MAX(salary),Min(Salary) 
from C 
GROUP BY id; 

這是給我的所有ID與它最大 ，我想只是ID與最大和工資最低！

Answer 1

Select id, 
salary 
from C 
where salary = (select MAX(salary) 
        from C) 

Answer 2

你有幾個選項，只需要該表的單次掃描：

SQL Fiddle

的Oracle 11g R2架構設置：

CREATE TABLE C (ID, SALARY) AS 
      SELECT 1, 100 FROM DUAL 
UNION ALL SELECT 2, 110 FROM DUAL 
UNION ALL SELECT 3, 100 FROM DUAL 
UNION ALL SELECT 4, 110 FROM DUAL 
UNION ALL SELECT 5, 90 FROM DUAL 

查詢1 - 獲取一個ID：

SELECT * 
FROM (
    SELECT ID, SALARY 
    FROM c 
    ORDER BY SALARY DESC 
) 
WHERE ROWNUM = 1 

Results：

| ID | SALARY | 
|----|--------| 
| 2 | 110 | 

查詢2 - 獲取一個單一ID（另一種方法，將獲得的最小和最大的ID）：

SELECT MAX(ID) KEEP (DENSE_RANK LAST ORDER BY SALARY) AS MAX_SALARY_ID, 
     MAX(SALARY) AS MAX_SALARY, 
     MIN(ID) KEEP (DENSE_RANK FIRST ORDER BY SALARY) AS MIN_SALARY_ID, 
     MIN(SALARY) AS MIN_SALARY 
FROM C 

Results：

| MAX_SALARY_ID | MAX_SALARY | MIN_SALARY_ID | MIN_SALARY | 
|---------------|------------|---------------|------------| 
|    4 |  110 |    5 |   90 | 

查詢3 - 獲取所有的ID與薪：

SELECT ID, SALARY 
FROM (
    SELECT ID, 
     SALARY, 
     RANK() OVER (ORDER BY SALARY DESC) AS RNK 
    FROM C 
) 
WHERE RNK = 1 

Results：

| ID | SALARY | 
|----|--------| 
| 2 | 110 | 
| 4 | 110 | 

查詢4 - 獲取最低和最高工資所有ID：

SELECT LISTAGG(CASE MIN_RANK WHEN 1 THEN ID END, ',') WITHIN GROUP (ORDER BY ID) AS MIN_SALARY_IDS, 
     MAX(CASE MIN_RANK WHEN 1 THEN SALARY END) AS MIN_SALARY, 
     LISTAGG(CASE MAX_RANK WHEN 1 THEN ID END, ',') WITHIN GROUP (ORDER BY ID) AS MAX_SALARY_IDS, 
     MAX(CASE MAX_RANK WHEN 1 THEN SALARY END) AS MAX_SALARY 
FROM (
    SELECT ID, 
     SALARY, 
     RANK() OVER (ORDER BY SALARY ASC) AS MIN_RANK, 
     RANK() OVER (ORDER BY SALARY DESC) AS MAX_RANK 
    FROM C 
) 

Results：

| MIN_SALARY_IDS | MIN_SALARY | MAX_SALARY_IDS | MAX_SALARY | 
|----------------|------------|----------------|------------| 
|    5 |   90 |   2,4 |  110 | 

查詢5：

SELECT ID, 
     SALARY, 
     CASE WHEN MIN_RANK = 1 THEN 'MIN' 
      WHEN MAX_RANK = 1 THEN 'MAX' END AS MIN_MAX 
FROM (
    SELECT ID, 
     SALARY, 
     RANK() OVER (ORDER BY SALARY ASC) AS MIN_RANK, 
     RANK() OVER (ORDER BY SALARY DESC) AS MAX_RANK 
    FROM C 
) 
WHERE MIN_RANK = 1 OR MAX_RANK = 1 

Results：

| ID | SALARY | MIN_MAX | 
|----|--------|---------| 
| 2 | 110 |  MAX | 
| 4 | 110 |  MAX | 
| 5 |  90 |  MIN | 

Answer 3

可以使用first_value或last_value

的FIRST_VALUE解析功能類似於第一解析 功能，讓您可以從一組有序返回的第一個結果。

https://oracle-base.com/articles/misc/first-value-and-last-value-analytic-functions

create table C (id int, salary int); 
insert into c values(1, 1); 
insert into c values(2, 2); 
insert into c values(3, 3); 
insert into c values(4, 4); 
insert into c values(5, 5); 

Select distinct first_value(id) over (order by salary desc) 
from C 

    FIRST_VALUE(ID)OVER(ORDERBYSAL 
1 5