選擇朋友的朋友sql的性能（但不是我的朋友）

Question

我想得到我的朋友不是我朋友的朋友。 我有一個表是這樣的： userFriends（ID用戶，idUserFriend）

我在想是這樣的：

select distinct idUserFriend from userFriends where idUser in 
(select idUserFriend from userFriends where idUser = 1) 
and idUserFriend not in (select idUserFriend from userFriends where idUser = 1) 

但我不知道它這麼慢，或者如果它可以更快其他方式。

對此有何看法？

Answer 1

SELECT DISTINCT 
    two.idUserFriend 
FROM userFriends one 
JOIN userFriends two ON one.idUserFriend = two.idUser 
WHERE NOT EXISTS (
     SELECT * 
     FROM userFriends nx 
     WHERE nx.idUser = one.idUser 
     AND nx.idUserFriend = two.idUserFriend 
     ) 
AND one.idUser = 1 
     ; 

同樣可以通過 「NOT IN」 來完成構建：

SELECT DISTINCT 
    two.idUserFriend 
FROM userFriends one 
JOIN userFriends two ON one.idUserFriend = two.idUser 
WHERE two.idUserFriend NOT IN (
     SELECT nx.idUserFriend 
     FROM userFriends nx 
     WHERE nx.idUser = one.idUser 
     ) 
AND one.idUser = 1 
     ; 

而且有 「除」 版本：

SELECT DISTINCT 
    two.idUserFriend 
FROM userFriends one 
JOIN userFriends two ON one.idUserFriend = two.idUser 
WHERE one.idUser = 1 
EXCEPT (
     SELECT nx.idUserFriend 
     FROM userFriends nx 
     WHERE nx.idUser = 1 
     ) 
     ; 

Answer 2

使用加入，使比較：

SELECT 
    b.idUserFriend 
FROM 
    userFriends a 
INNER JOIN 
    userFriends b ON a.idUserFriend = b.idUser 
LEFT JOIN 
    userFriends c ON a.idUser = c.idUser AND b.idUserFriend = c.idUserFriend 
WHERE 
    a.idUser = 1 
    AND c.idUser IS NULL 
GROUP BY 
    b.idUserFriend #eliminate duplicates 

通常情況下，最好是使用JOIN結束了子查詢，他們將利用上比較相關領域的指標。另一方面，子查詢將針對每個返回的行執行，即使它是不相關的子查詢（MySQL）。在JOINs vs Subqueries

Answer 3

select myFriend.idUserFriend from userFriend me inner join userFriends myFriend 
on me.idUserFriend = myFriend.idUser and myFriend.idUserFriend != me.idUserFriend 
where me.idUser='MyUserId'; 

Answer 4

更多信息試試這個 -

SELECT UF2.idUser, UF2.idUserFriend 
FROM USERFIRENDS UF2 INNER JOIN 
(
    SELECT idUser, idUserFriend 
    FROM USERFRIENDS UF1 
    WHERE UF1.idUser =1 -- this query gives my friend 
) MYFRIENDS ON 
     UF2.idUser=MYFRIENDS.idUserFriend -- get my freinds friends 
     AND UF2.idUserFriend NOT IN 
      (
       SELECT idUserFriend 
       FROM USERFRIENDS UF1 
       WHERE UF1.idUser =1   
      ) 

的優點與此查詢的第一子查詢是加入的一部分，對每條記錄將不被執行。

不幸的是，您需要在NOT IN情況下使用子查詢。