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我在FLEX中更新，目前我正在使用FLEX 3.0 我想在FLEX中開發Tic Tac Toe遊戲。起初我認爲這對我來說是最簡單的，但現在它對我來說會非常艱難。我在互聯網上搜索過，但沒有一個鏈接可以幫助我，所以請給我正確的想法與正確的代碼。在這裏，我給你的示例代碼。它有點複雜，所以很抱歉。Flex中的Tic Tac Toe遊戲
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="vertical" backgroundColor="#000000"
horizontalAlign="center" verticalAlign="middle" height="100%" width="100%" verticalGap="0" horizontalGap="0">
<mx:Script>
<![CDATA[
import mx.controls.Alert;
import mx.controls.Image;
private var blnFirst:Boolean = true;
private var arr0:Array = new Array();
private var arr1:Array = new Array();
private var arr2:Array = new Array();
private var count:int = 0;
private var arr:Array = new Array();
private var pl1Won:Boolean = false;
private var pl2Won:Boolean = false;
public function img_click(event:Event):void
{
if(event.currentTarget.enabled)
{
count++;
if(blnFirst)
{
blnFirst = false;
var itemp:Image = new Image();
itemp.percentHeight = 100;
itemp.percentWidth = 100;
itemp.source = "Images/Circle.png";
event.currentTarget.addChild(itemp);
event.currentTarget.enabled = false;
arrayInsert(event.currentTarget.id,true);
}
else
{
blnFirst = true;
var itemp:Image = new Image();
itemp.percentHeight = 100;
itemp.percentWidth = 100;
itemp.source = "Images/Cross.png";
event.currentTarget.addChild(itemp);
event.currentTarget.enabled = false;
arrayInsert(event.currentTarget.id,false);
}
}
if(count == 9)
{
arr = [arr0, arr1, arr2];
}
}
private function arrayInsert(id:String,value:Boolean):void
{
if(id == "box00")
arr0[0] = value;
if(id == "box01")
arr0[1] = value;
if(id == "box02")
arr0[2] = value;
if(id == "box10")
arr1[0] = value;
if(id == "box11")
arr1[1] = value;
if(id == "box12")
arr1[2] = value;
if(id == "box20")
arr2[0] = value;
if(id == "box21")
arr2[1] = value;
if(id == "box22")
arr2[2] = value;
}
private function btn_click():void
{
for(var i:int=0;i<3;i++)
{
for(var j:int=0;j<3;j++)
{
//very confused in this part
}
}
}
]]>
</mx:Script>
<mx:VBox height="500" width="500" borderStyle="solid" borderThickness="3" borderColor="#000000"
backgroundColor="#ffffff" verticalGap="0" horizontalGap="0">
<mx:HBox width="100%" height="33.3%" horizontalGap="0" verticalGap="0">
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box00" >
</mx:Box>
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box01">
</mx:Box>
<mx:Box height="100%" width="33.4%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box02">
</mx:Box>
</mx:HBox>
<mx:HBox width="100%" height="33.3%" horizontalGap="0" verticalGap="0">
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box10">
</mx:Box>
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box11">
</mx:Box>
<mx:Box height="100%" width="33.4%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box12">
</mx:Box>
</mx:HBox>
<mx:HBox width="100%" height="33.4%" horizontalGap="0" verticalGap="0">
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box20">
</mx:Box>
<mx:Box height="100%" width="33.3%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box21">
</mx:Box>
<mx:Box height="100%" width="33.4%" borderStyle="solid" borderThickness="3" borderColor="#000000" backgroundColor="#ffffff"
click="{img_click(event);}" id="box22">
</mx:Box>
</mx:HBox>
</mx:VBox>
<mx:Button click="{btn_click();}" />
</mx:Application>
我有檢查btn_click()功能的中獎條件，但你可以給我的想法去改變它完成一行時。我想知道如何處理TicTacToe遊戲的數組。
試着更多的是你想要達到的目標。好像你希望我們爲你完成遊戲。 – 2012-01-04 11:19:20
我希望根據我的實施情況以及在某個時間點獲勝的條件邏輯，如果某個人勝出，而不是在此時如何檢查此時所有包廂是否滿足勝利條件。所以我已經給了我的代碼。請幫幫我。 – 2012-01-04 11:27:07
我認爲你應該嘗試在一些較小的問題上分解這個大問題。這是一個廣泛的答案，快速而迅速地回答。 – 2012-01-04 11:40:40