我有這個hangman程序,但在詢問用戶他們是否想要再次玩時有問題,它總是隻是結束程序。我該如何解決這個問題。感謝未來的答覆。包裹hang子手 。我希望編輯是可以的使用if語句的循環問題
import java.io.File; import java.io.FileNotFoundException;
import java.util.Scanner;
public class Hangman {
static Scanner keyboard = new Scanner(System.in);
static int size, size2;
static boolean play = false;
static String word;
static String[] ARRAY = new String[0];
static String ANSI_RESET = "\u001B[0m";
static String ANSI_BLUE = "\u001B[34m";
static String ANSI_GREEN = "\u001B[32m";
static String ANSI_RED = "\u001B[31m";
static String ANSI_LIGHTBLUE = "\u001B[36m";
//^declarations for variables and colors for display^
public static void main(String[] args) {
randomWordPicking();
//^calls method^
}
public static void setUpGame() {
System.err.printf("Welcome to hangman.\n");
try {
Scanner scFile = new Scanner(new File("H:\\HangMan\\src\\hangman\\HangMan.txt"));
String line;
while (scFile.hasNext()) {
line = scFile.nextLine();
Scanner scLine = new Scanner(line);
size++;
}
ARRAY = new String[size];
Scanner scFile1 = new Scanner(new File("H:\\HangMan\\src\\hangman\\HangMan.txt"));
while (scFile1.hasNext()) {
String getWord;
line = scFile1.nextLine();
Scanner scLine = new Scanner(line);
word = scLine.next();
ARRAY[size2] = word;
size2++;
//calls method for picking word^
}
} catch (FileNotFoundException e) {
System.out.println(e);
}
}
public static void randomWordPicking() {
setUpGame();
int LEFT = 6;
do {
int random = (int) (Math.random() * ARRAY.length);
//^genertates a random number^
String randomWord = ARRAY[random];
String word = randomWord;
//^chosses a random word and asgins it to a variable^
char[] ranWord = randomWord.toCharArray();
char[] dash = word.toCharArray();
//^Creates a char array for the random word chosen and for the dashs which are displayed^
for (int i = 0; i < dash.length; i++) {
dash[i] = '-';
System.out.print(dash[i]);
//^displays dashs to the user^
}
for (int A = 1; A <= dash.length;) {
System.out.print(ANSI_BLUE + "\nGuess a Letter: " + ANSI_RESET);
String userletters = keyboard.next();
//^gets user input^
if (!userletters.equalsIgnoreCase(randomWord)) {
//^allows program to enter loop if user has entered a letter^
for (int i = 0; i < userletters.length(); i++) {
char userLetter = userletters.charAt(i);
String T = Character.toString(userLetter);
for (int B = 0; B < ranWord.length; B++) {
//^converts users input to a char and to a string^
if (userLetter == dash[B]) {
System.err.println("This " + userLetter + "' letter already exist");
B++;
//^tells user if the letter they entered already exists^
if (userLetter == dash[B - 1]) {
break;
}
} else if (userLetter == ranWord[B]) {
dash[B] = userLetter;
A--;
}
}
if (!(new String(ranWord).contains(T))) {
LEFT--;
System.out.println("You did not guess a correct letter, you have " + LEFT + " OF "
+ dash.length + " trys left to guess correctly");
}
//^shows how many trys the user has left to get the word right before game ends^
System.out.println(dash);
if (LEFT == 0) {
System.out.println("The word you had to guess was " + word);
break;
}
//^shows the user the word if they didnt guess correctly^
}
} else {
System.out.println(ANSI_GREEN + "\nYou have guessed the word correctly!" + ANSI_RESET);
break;
}
if (LEFT == 0) {
break;
}
if ((new String(word)).equals(new String(dash))) {
System.out.println(ANSI_GREEN + "\nYou have guessed the word correctly!" + ANSI_RESET);
break;
}
}
//^if user enters the word it will check and then display that they got the word correct^
System.out.println("Play agian? (y/n)");
String name = keyboard.next();
//^asks user if they want to play again^
if (name.equalsIgnoreCase("n")) {
play = true;
return;
}
//^stops program if user enters n to stop game^
} while (play = false);
}
}
據我瞭解,你要調用方法'playOn()'。然而,我不知道你在哪裏叫它。 – AlexR
@AlexR我把方法中的代碼放到了它應該在的地方 –