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這是一個後續問題Issue in deleting supersets in Matlab。在前面的問題我被刪除集,並且保持子集,我有一個工作的答案,現在我想有子集來替代超集,而不是刪除它們,比如我有一個數據設置如下:如何用matlab中的子集替換超集?
a{1} = [5]
a{2} = [4 11 14]
a{3} = [1]
a{4} = [5 16]
a{5} = [5]
a{6} = [11 16]
a{7} = [11]
a{8} = [16]
a{9} = [9 14 17]
a{10} = [14]
[ii, jj] = ndgrid(1:numel(a));
s = cellfun(@(x,y) all(ismember(x,y)), a(ii), a(jj));
% Set diagonal to zero.
s = s - diag(diag(s));
% Indicator matrix for sets that are exactly equal.
same = s & s';
% For equal sets keep only the first occurence.
keep = triu(same) | ~same.*s;
% Delete supersets.
similarity = a(~any(keep,1));
celldisp(similarity)
當我上面的代碼運行的結果如下:
a{1} = [5]
a{2} = [1]
a{3} = [11]
a{4} = [16]
a{5} = [14]
我想要做的是與子集來替代超集,而不是刪除它們:
預期的輸出應該如下:
a{1} = [5]
a{2} = [11]
a{3} = [1]
a{4} = [5]
a{5} = [5]
a{6} = [11]
a{7} = [11]
a{8} = [16]
a{9} = [14]
a{10} = [14]
請解釋預期的輸出。爲什麼是'4而不是16'?這是否重要或應該挑選現有子集? – Daniel
,因爲在一個循環中,當我們從上到下,單個值「5」出現時,我們從成對開始,並且如果在「a {4}」中有'16'而不是'16' '在位置'a {4}' –
目前還不清楚你在問什麼。獲得該輸出的準則是什麼? –