如果值通過if/then語句從數組中移除元素 - Javascript

Question

我正在循環數組中的元素。如果某個值不在特定範圍內，我想刪除該元素（與該值關聯）。

這是我到目前爲止（請參閱下面的代碼） - 我使用彈出方法刪除元素，因爲它通過，但數組中的最後一個元素總是被刪除，而不是元素/值在if​​ /然後聲明。我也嘗試了拼接方法，但是我無法讓它工作。任何想法如何做到這一點？

var h = [ 
 
    \t ["29","Verbena St", "500", "2", "2,702"], 
 
    \t ["36", "Quitman St", "400", "2", "1,700"], 
 
    \t ["32", "Alan Dr", "500", "2", "2,408"], 
 
    \t ["34", "Newton St", "300", "2", "1,954"], 
 
    \t ["30", "Soth Pl", "400", "2", "1,509"] 
 
    ]; 
 

 
    var hs = [ 
 
     \t ["Verbena St"], 
 
    \t ["Quitman St"], 
 
     ["Alan Dr"], 
 
     \t ["Newton St"], 
 
     \t ["Soth Pl"] 
 
    ]; 
 

 

 
function Location(){ 
 

 
    for (var r = 0; r <= h.length; r++){ 
 
     var p = h[r][0]; 
 
\t  var address = h[r][1]; // Get address 
 
     if (p >= 21 && p <= 33 && address == hs[r]){ 
 
      console.log(address); 
 
     } 
 
     else { 
 
      console.log(address + " - OVER 33"); 
 
      h.pop(address); 
 
      console.log(address + " - REMOVED"); 
 
     } 
 
    } 
 
}; 
 

 
Location();

Answer 1

這不是很好的做法，通過它迭代從數組中刪除元素，相反，則可以使用filter()過濾，像這樣：

var h = [ 
 
    ["29","Verbena St", "500", "2", "2,702"], 
 
    ["36", "Quitman St", "400", "2", "1,700"], 
 
    ["32", "Alan Dr", "500", "2", "2,408"], 
 
    ["34", "Newton St", "300", "2", "1,954"], 
 
    ["30", "Soth Pl", "400", "2", "1,509"] 
 
]; 
 

 
var hs = [ 
 
    ["Verbena St"], 
 
    ["Quitman St"], 
 
    ["Alan Dr"], 
 
    ["Newton St"], 
 
    ["Soth Pl"] 
 
]; 
 

 
function Location(){ 
 
    h = h.filter(function(r, i){ // r = value, i = index 
 
    var p=r[0]; 
 
    var address = r[1]; // Get address 
 
    return p >= 21 && p <= 33 && address == hs[i]; 
 
    }); 
 
}; 
 

 
Location(); 
 
console.log(h);

或者，如果你想顯示消息ES，您可以使用另一個陣列，只推你想它的元素（最好使用foreach）：

var h = [ 
 
    ["29","Verbena St", "500", "2", "2,702"], 
 
    ["36", "Quitman St", "400", "2", "1,700"], 
 
    ["32", "Alan Dr", "500", "2", "2,408"], 
 
    ["34", "Newton St", "300", "2", "1,954"], 
 
    ["30", "Soth Pl", "400", "2", "1,509"] 
 
]; 
 

 
var hs = [ 
 
    ["Verbena St"], 
 
    ["Quitman St"], 
 
    ["Alan Dr"], 
 
    ["Newton St"], 
 
    ["Soth Pl"] 
 
]; 
 

 
function Location(){ 
 
    var g = []; 
 
    h.forEach(function(r, i){ // r = value, i = index 
 
    var p = r[0]; 
 
    var address = r[1]; // Get address 
 
    if (p >= 21 && p <= 33 && address == hs[i]){ 
 
    \t console.log(address); 
 
     g.push(r); // push it 
 
    } 
 
    else{ 
 
     console.log(address + " - OVER 33 - REMOVED"); // do nothing 
 
    } 
 
    }); 
 
    h = g; 
 
} 
 

 
Location(); 
 
console.log(h);

Answer 2

用於去除數組的元素，你可以從端部線圈和必要時進行拼接，因爲下一個較小的索引不受影響。

function updateLocation() { 
 
    var address, p, r = h.length; 
 
    while (r--) { 
 
     p = h[r][0]; 
 
     address = h[r][1]; // Get address 
 
     if (p >= 21 && p <= 33 && address == hs[r]) { 
 
      console.log(address); 
 
     } else { 
 
      console.log(address + " - OVER 33"); 
 
      h.splice(r, 1); 
 
      console.log(address + " - REMOVED"); 
 
     } 
 
    } 
 
} 
 

 
var h = [["29", "Verbena St", "500", "2", "2,702"], ["36", "Quitman St", "400", "2", "1,700"], ["32", "Alan Dr", "500", "2", "2,408"], ["34", "Newton St", "300", "2", "1,954"], ["30", "Soth Pl", "400", "2", "1,509"]], 
 
    hs = [["Verbena St"], ["Quitman St"], ["Alan Dr"], ["Newton St"], ["Soth Pl"]]; 
 

 
updateLocation(); 
 
console.log(h);