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我有一個簡單的彈簧集成項目,其中我連接到簡單的肥皂服務 http://www.w3schools.com/webservic/tempconvert.asmx來轉換溫度。如何將肥皂響應pojo?
下面是XML定義鏈皁服務:
<beans:beans
...
<chain input-channel="fahrenheitChannel" output-channel="celsiusChannel">
<ws:header-enricher>
<ws:soap-action value="http://www.w3schools.com/webservices/FahrenheitToCelsius"/>
</ws:header-enricher>
<ws:outbound-gateway uri="http://www.w3schools.com/webservices/tempconvert.asmx"/>
</chain>
<!-- The response from the service is logged to the console. -->
<stream:stdout-channel-adapter id="celsiusChannel"/>
</beans:beans>
,這裏是演示類,通過輸入信道發送消息:
public class WebServiceDemoTestApp {
public static void main(String[] args) {
ClassPathXmlApplicationContext context =
new ClassPathXmlApplicationContext("/META-INF/spring/integration/temperatureConversion.xml");
ChannelResolver channelResolver = new BeanFactoryChannelResolver(context);
// Compose the XML message according to the server's schema
String requestXml =
"<FahrenheitToCelsius xmlns=\"http://www.w3schools.com/webservices/\">" +
" <Fahrenheit>90.0</Fahrenheit>" +
"</FahrenheitToCelsius>";
// Create the Message object
Message<String> message = MessageBuilder.withPayload(requestXml).build();
// Send the Message to the handler's input channel
MessageChannel channel = channelResolver.resolveChannelName("fahrenheitChannel");
channel.send(message);
}
}
它工作正常,我在這裏是響應:
<FahrenheitToCelsiusResponse xmlns="http://www.w3schools.com/webservices/"><FahrenheitToCelsiusResult>32.2222222222222</FahrenheitToCelsiusResult></FahrenheitToCelsiusResponse>
現在,我該如何編寫XML簡單pojo對象的響應呢?
如果有人可以發佈一些代碼示例。
http://blog.bdoughan.com/2012/08/handle-middle-of-xml-document-with-jaxb.html - FYR ... –