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我有以下種類的JSON,我想找到與JSON的Status : 1
對象的數量,我已經嘗試了下面的方法,它不工作。角度JS控制器與JSON陣列的對象過濾器
而且我知道NG-過濾器需要僅適用於數組,但我沒有找到一個方法來做到這一點在下面的JSON數據,有人可以幫助我
預期我得到錯誤,但如何解決這個問題在我的情況
[filter:notarray] Expected array but received:
在下面的JSON數據正如你看到的我有陣列陣列,我應該得到的 伯爵狀態值爲1
期望輸出
計數第一陣列的:第二陣列的1個 計數:1
JSON數據
[
[{
"id": 252323,
"orderId": 223505,
"status": 1,
"executedOn": "13/Sep/17",
"executedBy": "Person A",
"executedByDisplay": "Person A",
"cycleId": 3994,
"cycleName": "Cycle A",
"versionId": 21291,
"versionName": "Version A",
"issueKey": "Key-12561"
}],
[{
"id": 253077,
"orderId": 224047,
"status": 1,
"executedOn": "26/Sep/17",
"executedBy": "Person B",
"executedByDisplay": "Person B",
"cycleId": 4012,
"cycleName": "Cycle B",
"versionId": 22912,
"versionName": "Version B",
"issueKey": "Key-12580"
}, {
"id": 253076,
"orderId": 224046,
"status": 2,
"executedOn": "20/Sep/17",
"executedBy": "Person B",
"executedByDisplay": "Person B",
"cycleId": 4012,
"cycleName": "Cycle B",
"versionId": 22912,
"versionName": "Version B",
"issueKey": "Key-12578"
}, {
"id": 253075,
"orderId": 224045,
"status": 1,
"executedOn": "20/Sep/17",
"executedBy": "Person B",
"executedByDisplay": "Person B",
"cycleId": 4012,
"cycleName": "Cycle B",
"versionId": 22912,
"versionName": "Version B",
"issueKey": "Key-12582"
}, {
"id": 253074,
"orderId": 224044,
"status": 1,
"executedOn": "20/Sep/17",
"executedBy": "Person B",
"executedByDisplay": "Person B",
"cycleId": 4012,
"cycleName": "Cycle B",
"versionId": 22912,
"versionName": "Version B",
"issueKey": "Key-12584"
}],
[{
"id": 255168,
"orderId": 226138,
"status": 1,
"executedOn": "26/Sep/17",
"executedBy": "Person A",
"executedByDisplay": "Person A",
"cycleId": 4022,
"cycleName": "Cycle C",
"versionId": 21291,
"versionName": "Version A",
"issueKey": "Key-12617"
}]
]
:第三陣列的3 計數
Angular JS Code
var app = angular.module('studentApp', []);
app.controller('StudentCntrl', function($scope, $http, $filter) {
$http.get('data.json').then(function(response) {
$scope.value = response.data;
$scope.value.forEach(function(items) {
$scope.eachValue = items;
items.forEach(function(insideItems) {
passvalue = $filter('filter')(insideItems, function(inputs) {
if (inputs.status == '1')
console.log(inputs.length);
return inputs;
});
});
});
});
});
由於這是我想要的!有沒有什麼辦法,我可以實現與角js過濾相同的東西 – Batman
亞肯定檢查更新的答案 – jitender
謝謝它的作品像魅力! – Batman