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在Scala中,我似乎無法十六進制的字符串轉換回整數:斯卡拉十六進制字符串到整數轉換
val cols = Array(0x2791C3FF, 0x5DA1CAFF, 0x83B2D1FF, 0xA8C5D8FF,
0xCCDBE0FF, 0xE9D3C1FF, 0xDCAD92FF, 0xD08B6CFF,
0xC66E4BFF, 0xBD4E2EFF)
cols.map({ v => Integer.toHexString(v)}).map(v => Integer.parseInt(v, 16))
我收到以下錯誤信息:
java.lang.NumberFormatException: For input string: "83b2d1ff"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:583)
at $anonfun$3.apply(<console>:12)
at $anonfun$3.apply(<console>:12)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:245)
at scala.collection.TraversableLike$$anonfun$map$1.apply(TraversableLike.scala:245)
at scala.collection.IndexedSeqOptimized$class.foreach(IndexedSeqOptimized.scala:33)
at scala.collection.mutable.ArrayOps$ofRef.foreach(ArrayOps.scala:186)
at scala.collection.TraversableLike$class.map(TraversableLike.scala:245)
at scala.collection.mutable.ArrayOps$ofRef.map(ArrayOps.scala:186)
... 35 elided