JavaScript的遞歸函數調用覆蓋

Question

我有一個函數：

function brackets(openStock, closeStock, s) { 
    if (openStock == 0 && closeStock == 0) { 
    document.getElementById('demo').innerHTML = s; 
    } 

    if (openStock > 0) { 
    brackets(openStock - 1, closeStock + 1, s + "("); 
    } 
    if (closeStock > 0) { 
    brackets(openStock, closeStock - 1, s + ")"); 
    } 
} 

應該parenthesizes的組合編寫成一段「演示」但是寫的第一個之後，其他的人都沒有寫進段。由於它是一個遞歸函數，我不知道如何連接結果（組合）。

Answer 1

function brackets(openStock, closeStock,s) 
{ 
    if (openStock == 0 && closeStock == 0) { 
     var e = document.createElement('div'); 
     e.innerHTML = s; 

     while(e.firstChild) { 
      document.getElementById('demo').appendChild(e.firstChild); 
     } 
    } 

    if (openStock > 0) { 
     brackets(openStock-1, closeStock+1, s + "("); 
    } 
    if (closeStock > 0) { 
     brackets(openStock, closeStock-1, s + ")"); 
    } 
}