如何從ExternalContext獲取webapp的絕對URL？

Question

我正在嘗試從ExternalContext的web應用程序的根URL，但無法瞭解使用哪種方法？

Answer 1

您可以從FacesContext得到ExternalContext，並從外部環境抽取request然後

String file = request.getRequestURI(); 
if (request.getQueryString() != null) { 
    file += '?' + request.getQueryString(); 
} 
URL reconstructedURL = new URL(request.getScheme(), 
           request.getServerName(), 
           request.getServerPort(), 
           file); 
reconstructedURL.toString(); 

source

Answer 2

讓我重新短語Jigar的回答有點：

final ExternalContext ectx = context.getExternalContext(); 
String url = ectx.getRequestScheme() 
    + "://" + ectx.getRequestServerName() 
    + ":" + ectx.getRequestServerPort() 
    + "/" + ectx.getRequestContextPath(); 

Answer 3

一個更簡潔的方法是：

HttpServletRequest request = (HttpServletRequest) externalContext.getRequest(); 
String url = request.getRequestURL().toString(); 
String baseURL = url.substring(0, url.length() - request.getRequestURI().length()) + request.getContextPath() + "/"; 

那麼你不需要用省略端口撥弄時，方案是http和端口是80等。

Answer 4

這是我發現的最簡單的方法，它不涉及URL各個部分的神祕字符串處理。它似乎適用於所有情況，包括不同的協議和端口。

String getAbsoluteApplicationUrl() throws URISyntaxException { 
     ExternalContext externalContext = FacesContext.getCurrentInstance().getExternalContext(); 
     HttpServletRequest request = (HttpServletRequest) externalContext.getRequest(); 
     URI uri = new URI(request.getRequestURL().toString()); 
     newUri = new URI(uri.getScheme(), null, 
       uri.getHost(), 
       uri.getPort(), 
       request.getContextPath().toString(),null, null); 
     return newUri.toString(); 
} 

Answer 5

我有一個類似BalusC的：

FacesContext context = FacesContext.getCurrentInstance(); 
HttpServletRequest request = (HttpServletRequest)context.getExternalContext().getRequest(); 
String requestURL = request.getRequestURL().toString(); 
String url = requestURL.substring(0, requestURL.lastIndexOf("/"));