我目前有一個系統,輸出一個等待時間,給定他們的到達時間和當前時間; (當前時間 - 到達時間)。我將如何編程代碼以便SQL時間超過
if the waiting_time exceeds 3 hours then alert "patient must be seen next!"
這是我迄今爲止計算waiting_time的代碼。
<?php
$conn = mysqli_connect("localhost","root","") or die ("No connection");
mysqli_select_db($conn, "a&e") or die('Could not select database.');
$query = "SELECT PatientID, Forename, Surname, Gender, Illness, Priority, Arrival_time, TIME_FORMAT(ABS(TIMEDIFF(CURTIME(), Arrival_time)),'%H hours') as Waiting_Time FROM Patient";
$result = mysqli_query($conn, $query) or die("Invalid query");
echo "<table border='1'>
<tr>
<th>PatientID</th>
<th>Forename</th>
<th>Surname</th>
<th>Gender</th>
<th>Illness</th>
<th>Priority</th>
<th>Waiting Time</th>
</tr>";
while ($row = $result->fetch_object()){
echo "<tr>
<td>" . $row->PatientID . "</td>
<td>" . $row->Forename . "</td>
<td>" . $row->Surname . "</td>
<td>" . $row->Gender . "</td>
<td>" . $row->Illness . "</td>
<td>" . $row->Priority . "</td>
<td>" . $row->Waiting_Time . "</td>
</tr>";
}
echo "</table>";
mysqli_close($conn);
?>
您駕駛室檢查在到達時間和當前時間之間經過多少分鐘,如果> 180(3小時* 60分鐘),則顯示某種警報/通知。您也可以通過等待時間排序desc SELECT NOW(),TIMESTAMPDIFF(MINUTE,'2013-03-26 08:24; 15',NOW())AS WaitTime,IF(TIMESTAMPDIFF(MINUTE,'2013-03-26 08 :24; 15',NOW())> = 180,'alert','na');希望這有助於 – 2013-03-26 15:42:04
我如何檢查到達時間和當前時間之間已經過了多少分鐘? – 2013-03-26 15:55:22
檢查TIMESTAMPDIFF的語法 – 2013-03-26 15:56:30