我想要做一個選擇查詢使用JavaScript參數($ userCard)獲取在同一個函數(代碼下面)。但給出了一個未定義的變量錯誤,如何在查詢中傳遞參數?選擇查詢使用JavaScript的文字
<script>
function count() {
$card = "V010";
$userCard = document.getElementById('visitorID');
if($userCard.value.length == 4){
<?php
$connection = connectToSql();
$query = "SELECT * FROM visitorsystem.visitor WHERE cardNo = '$userCard' ";
$result = mysqli_query($connection,$query)
or die("Error in query: ". mysqli_error($connection));
if(mysqli_fetch_assoc($result) >0)
{
echo "Card in Use";
}
?>
}
}
</script>
你希望獲得價值? '$ userCard = document.getElementById('visitorID').value' - 很難猜測沒有看到你的html –