Django-1.4.1：無法保存對象

Question

我的項目使用Django-1.2.5和Djando-1.3.1正常工作，但與Django-1.4.1不兼容。

我不能夠保存/創建一個對象，並得到一個錯誤下面給出：

from entry.models import Entry 

import datetime 

from publications.models import Publication 

e = Entry(title=u'this is a test headline to test django-1.4.1', 
      body_html=u'this is a test body data to test django-1.4.1', 
      pub_date=datetime.datetime.now(), 
      publication=Publication.objects.get(id=1)) 

e.save() 

錯誤：

Traceback (most recent call last): 
File "<console>", line 1, in <module> 
File "/home/admin/banking_code/contify-banking/entry/models.py", line 112, in save 
    super(Entry, self).save() 
File "/home/admin/banking_code/contify-banking/django/db/models/base.py", line 463, in save 
    self.save_base(using=using, force_insert=force_insert, force_update=force_update) 
File "/home/admin/banking_code/contify-banking/django/db/models/base.py", line 551, in save_base 
    result = manager._insert([self], fields=fields, return_id=update_pk, using=using, raw=raw) 
File "/home/admin/banking_code/contify-banking/django/db/models/manager.py", line 203, in _insert 
    return insert_query(self.model, objs, fields, **kwargs) 
File "/home/admin/banking_code/contify-banking/django/db/models/query.py", line 1593, in insert_query 
    return query.get_compiler(using=using).execute_sql(return_id) 
File "/home/admin/banking_code/contify-banking/django/db/models/sql/compiler.py", line 914, in execute_sql 
    return self.connection.ops.fetch_returned_insert_id(cursor) 
File "/home/admin/banking_code/contify-banking/django/db/backends/__init__.py", line 548, in fetch_returned_insert_id 
    return cursor.fetchone()[0] 
TypeError: 'NoneType' object is not subscriptable 

任何一個能幫助我嗎？

Answer 1

您可以驗證ID = 1的發佈對象是否存在？要做到這一點，最快的方式是通過Python的外殼：

運行「蟒蛇manage.py殼」從你的Django項目的主文件夾，然後：

>> from publications.models import Publication 
>> p = Publication.objects.get(id=1) 
>> p 

如果成功（你得到一個出版物體身份證1）那麼我們將不得不考慮一個更奇特的失敗原因。如果失敗，問題將被縮小到發佈模型定義的問題。