骰子重複需要幫助

-1

嗨，我已經做了這個隨機骰子游戲，需要幫助創建一個循環，讓我當用戶輸入一個無效的數字我想他們再試一次。這裏是我的代碼請幫忙！骰子重複需要幫助

import random 
dice = int(input("What sided dice do you want to use? (e.g. 4, 6 or 12): ")) 
if dice == 4: 
       random_number = int(random.randrange(1,4)) 
       print ("You selected a 4 sided dice") 
       print ("Your dice has rolled ") 
       print (random_number) 
elif dice == 6: 
       random_number2 = int(random.randrange(1,6)) 
       print ("You selected a 6 sided dice") 
       print("Your dice has rolled ") 
       print (random_number2) 
elif dice == 12: 
       random_number3 = int(random.randrange(1,12)) 
       print ("You selected a 12 sided dice") 
       print("Your dice has rolled ") 
       print (random_number3) 
else: 
       print(("You didn't select a valid sided dice, try again!"))*

來源

2013-12-11 James

注意'random.randrange'不包括端點，所以'randrange（1,4） '只會給你任何'[1,2,3]'。 –

這段代碼中有很多*重複;你可以使用'dice'變量來削減它的三分之二（例如'random.randrange（1，dice + 1'）。 – jonrsharpe

使用while循環：

import random 
dice = None 
while dice not in (4, 6, 12): 
    dice = int(input("What sided dice do you want to use? (e.g. 4, 6 or 12): ") 
if dice == 4: 
      random_number = int(random.randrange(1,4)) 
      print ("You selected a 4 sided dice") 
      print ("Your dice has rolled ") 
      print (random_number) 
elif dice == 6: 
      random_number2 = int(random.randrange(1,6)) 
      print ("You selected a 6 sided dice") 
      print("Your dice has rolled ") 
      print (random_number2) 

elif dice == 12: 
      random_number3 = int(random.randrange(1,12)) 
      print ("You selected a 12 sided dice") 
      print("Your dice has rolled ") 
      print (random_number3)

來源

2013-12-11 09:20:29 aIKid

歡呼這個工程！ – James

如果你覺得這個答案有幫助，請[接受答案]（http://meta.stackexchange.com/questions/5234/how-does-accepting-an-answer-work）:) – aIKid

我建議使用一個短循環，提示，直到它得到一個有效的響應，然後切換基於輸入。這更容易出錯;如果任何一個案例缺少一個「break」，它就有一個bug。 – user2357112

你需要兩樣東西對於這樣的：

一個while循環，以保持繞來繞去，直到你得到你想要的東西;和
收集可接受的答案來檢查。

例如，一個簡單的解決辦法是用包裹當前的input聲明：

dice = 0 
while dice not in (4, 6, 12): 
    dice = ... 
# continue

來源

2013-12-11 09:21:18 jonrsharpe

骰子重複需要幫助

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