我有一個適用於我的解決方案。
private void refreshPostIt()
{
// Button btn; is defined somewhere else
Storyboard sb = new Storyboard();
DoubleAnimation rotate = new DoubleAnimation();
rotate.From = 0;
rotate.To = 360;
rotate.RepeatBehavior = RepeatBehavior.Forever;
RotateTransform rt = new RotateTransform();
btn.RenderTransformOrigin = new Point(0.5, 0.5);
btn.RenderTransform = rt;
Storyboard.SetTarget(rotate, btn);
Storyboard.SetTargetName(rotate, btn.Name);
Storyboard.SetTargetProperty(rotate, new PropertyPath("(UIElement.RenderTransform).(RotateTransform.Angle)"));
sb.Children.Add(rotate);
sb.Begin(btn, true);
// Do your stuff here (Not in the UI Thread)
// Maybe use a semaphore to lock the sb.Stop(btn)
sb.Stop(btn);
}
整個示例代碼:
public partial class Window1 : Window
{
Button btn;
Storyboard sb;
public Window1()
{
btn = new Button();
InitializeComponent();
this.grid.Children.Add(btn);
refreshPostIt();
}
private void refreshPostIt()
{
// Button btn; is defined somewhere else
sb = new Storyboard();
DoubleAnimation rotate = new DoubleAnimation();
rotate.From = 0;
rotate.To = 360;
rotate.RepeatBehavior = RepeatBehavior.Forever;
RotateTransform rt = new RotateTransform();
btn.RenderTransformOrigin = new Point(0.5, 0.5);
btn.RenderTransform = rt;
Storyboard.SetTarget(rotate, btn);
Storyboard.SetTargetName(rotate, btn.Name);
Storyboard.SetTargetProperty(rotate, new PropertyPath("(UIElement.RenderTransform).(RotateTransform.Angle)"));
sb.Children.Add(rotate);
sb.Begin(btn, true);
BackgroundWorker asd = new BackgroundWorker();
asd.DoWork += new DoWorkEventHandler(asd_DoWork);
asd.RunWorkerCompleted += new RunWorkerCompletedEventHandler(asd_RunWorkerCompleted);
asd.RunWorkerAsync();
}
void asd_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
if (sb != null)
{
sb.Stop(btn);
}
}
void asd_DoWork(object sender, DoWorkEventArgs e)
{
Thread.Sleep(2000);
}
}
好吧,我想解釋什麼,我認爲是你的問題就在這裏。當你使用UI-Thread來完成你的「工作」時,它不能更新你的UI,雖然不會動畫旋轉,當它完成你的「工作」時,在開始和停止動畫之間,最後會有時間要更新用戶界面,請致電停止動畫。這導致不顯示任何動畫。您需要將工作放在不同的線程中以防止發生這種情況。
希望有所幫助。
你的「一些代碼」在一個單獨的線程?或者不管怎樣都不會阻止執行下面的代碼? – peer
不,這是同一個線程,同步。 –
呼叫存在和停止之間需要多少時間?也許,動畫運行速度太快。 –