了迭代的節點的XPath的價值我有一個XML掌握在Java中
<?xml version="1.0" encoding="UTF-8"?>
<information>
<person id="1">
<name>Deep</name>
<age>34</age>
<gender>Male</gender>
</person>
<person id="2">
<name>Kumar</name>
<age>24</age>
<gender>Male</gender>
</person>
<person id="3">
<name>Deepali</name>
<age>19</age>
<gender>Female</gender>
</person>
<!-- more persons... -->
</information>
DocumentBuilderFactory domFactory = DocumentBuilderFactory
.newInstance();
domFactory.setNamespaceAware(true);
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document doc = builder.parse("persons.xml");
XPath xpath = XPathFactory.newInstance().newXPath();
// XPath Query for showing all nodes value
XPathExpression expr = xpath.compile("//information/person[0]/name/text()");
Object result = expr.evaluate(doc, XPathConstants.NODE);
Node node = (Node) result;
System.out.println(node.getNodeValue());
,我需要提取的第一人我想上面的代碼名稱它給例外任何一個可以幫我在這,
修訂 異常
Exception in thread "main" java.lang.ClassCastException: com.sun.org.apache.xerces.internal.dom.DeferredTextImpl cannot be cast to javax.xml.soap.Node
at xml.main(xml.java:33)
修訂ANSWER
XPathExpression expr = xpath.compile("//information/person[1]/name");
String str = (String) expr.evaluate(doc, XPathConstants.STRING);
System.out.println(str);
什麼異常? – McDowell 2012-04-11 18:12:50
拉梅什,假設我去看了醫生,說:「我覺得噁心,但我不會告訴你我的症狀,你能幫我嗎?」 – LarsH 2012-04-11 18:48:18
對不起,不提供例外。我已經更新了這個問題,請看看 – Ramesh 2012-04-12 04:06:37