無法使用LIKE與％或*

來搜索MS Access數據庫我試圖從我的java代碼中查詢MS Access數據庫，並且我沒有運氣，我閱讀的％通配符應該可以在其他帖子中使用。如果我從代碼中排除通配符併爲searchText變量提供與記錄Description完全匹配的值，那麼LIKE運算符可以工作。以下是我嘗試過的字符串查詢，它們返回null或發生異常：無法使用LIKE與％或*

String tableName =「SSPWO」; String desc =「[Description]」;

String query = String.format("SELECT * FROM %s WHERE " + desc + " LIKE '%" searchText + "%' ORDER BY [WorkOrderNo] DESC", tableName);

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String tableName =「SSPWO」; String desc =「[Description]」;

String query = String.format("SELECT * FROM %s WHERE " + desc + " LIKE '*" searchText + "*' ORDER BY [WorkOrderNo] DESC", tableName);

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String tableName =「SSPWO」; String desc =「[Description]」;

String query = String.format("SELECT * FROM %s WHERE " + desc + " LIKE \"%" searchText + "%\" ORDER BY [WorkOrderNo] DESC", tableName);

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String tableName =「SSPWO」; String desc =「[Description]」;

String query = String.format("SELECT * FROM %s WHERE " + desc + " LIKE \'%" searchText + "%\' ORDER BY [WorkOrderNo] DESC", tableName);

任何幫助，非常感謝。

來源

2014-02-20 user3334496

不要只說「空或異常」：郵政爲每個堆棧跟蹤失敗的案件。（另外，您應該使用準備好的語句而不是字符串粘貼來構建查詢。） – chrylis

百分號（%）絕對是正確的通配符在這種情況下使用。對於測試數據

ID Description       
-- ----------------------------------- 
1 I like apple pie.     
2 This is a test.      
3 Apple makes iThings.    
4 This is another test.    
5 Name of a tropical fruit: pineapple

代碼

String tableName = "SSPWO"; 
String desc = "[Description]"; 
String searchText = "apple"; 
PreparedStatement ps = con.prepareStatement(
     String.format("SELECT * FROM %s WHERE %s LIKE ?", tableName, desc) 
     ); 
ps.setString(1, "%" + searchText + "%"); 
ResultSet rs = ps.executeQuery(); 
while (rs.next()) { 
    System.out.println(String.format("%d: %s", rs.getInt(1),rs.getString(2))); 
}

生成以下控制檯輸出

1: I like apple pie. 
3: Apple makes iThings. 
5: Name of a tropical fruit: pineapple

來源

2014-02-20 22:00:45

謝謝。這工作。準備好的聲明絕對是要走的路。 – user3334496

你得反正語法錯誤的失衡：

String query = String.format([..snip...] + " LIKE '%" searchText 
                ^---missing +

來源

2014-02-20 20:38:07

無法使用LIKE與％或*

回答

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