需要使用SQL將多行連接成單個單元格？

Question

目前，我已經寫了：

SELECT IT_ID, SUBSTR (SYS_CONNECT_BY_PATH (grp , ','), 2) GROUPS 
FROM (SELECT U.IT_ID, LAST_NAME, FIRST_NAME, GRP, ROW_NUMBER() OVER (ORDER BY U.IT_ID) rn, COUNT(*) OVER() cnt 
FROM ECG_IT_USERS U 
JOIN SECUREGROUPS G ON U.IT_ID = G.IT_ID) 

START WITH rn = 1 
CONNECT BY rn = PRIOR rn + 1 

這將返回：

IT_ID GROUPS 

afz23 ADMIN 
afz23 ADMIN,QA 
alv77 ADMIN,QA,USER 
jaj23 ADMIN,QA,USER,USER 
klo26 ADMIN,QA,USER,USER,PROD 
klo26 ADMIN,QA,USER,USER,PROD,ADMIN 
klo26 ADMIN,QA,USER,USER,PROD,ADMIN,QA 
mav45 ADMIN,QA,USER,USER,PROD,ADMIN,QA,ADMIN 

我想不通我怎麼可以讓它重新遇到一個新用戶後？它似乎在繼續前面的組，即使用戶不屬於他們。

我需要看到：

IT_ID GROUPS 

afz23 ADMIN,QA 
alv77 USER 
jaj23 USER 
klo26 PROD,ADMIN,QA 
mav45 ADMIN 

Answer 1

有你需要做三件事情。

首先，您需要向row_number函數添加一個分區，以便每個IT_ID從1開始編號。您還需要將IT_ID列添加到連接方式，以便僅採用具有相同IT_ID值的行。最後，您需要按it_id列進行分組以刪除重複的行。

最後的查詢將

with ECG_IT_USERS as (
    select 'afz23' as it_id from dual union all 
    select 'alv77' as it_id from dual union all 
    select 'jaj23' as it_id from dual union all 
    select 'klo26' as it_id from dual union all 
    select 'mav45' as it_id from dual 
), 
securegroups as (
    select 'afz23' as it_id, 'ADMIN' as grp from dual union all 
    select 'afz23' as it_id, 'QA' as grp from dual union all 
    select 'alv77' as it_id, 'USER' as grp from dual union all 
    select 'jaj23' as it_id, 'USER' as grp from dual union all 
    select 'klo26' as it_id, 'PROD' as grp from dual union all 
    select 'klo26' as it_id, 'ADMIN' as grp from dual union all 
    select 'klo26' as it_id, 'QA' as grp from dual union all 
    select 'mav45' as it_id, 'ADMIN' as grp from dual 
) 
SELECT 
    IT_ID, 
    Max(SUBSTR (SYS_CONNECT_BY_PATH (grp , ','), 2)) GROUPS 
FROM (
    SELECT 
    U.IT_ID, 
-- LAST_NAME, 
-- BFIRST_NAME, 
    GRP, 
    ROW_NUMBER() OVER (partition by u.it_id ORDER BY U.IT_ID) rn, 
    COUNT(*) OVER() cnt 
FROM ECG_IT_USERS U 
JOIN SECUREGROUPS G ON (U.IT_ID = G.IT_ID)) 
START WITH rn = 1 
CONNECT BY rn = PRIOR rn + 1 and it_id = prior it_id 
Group by it_id 

這就產生了我下面的輸出：

IT_ID GROUPS 
----- -------------------- 
alv77 USER 
afz23 ADMIN,QA 
jaj23 USER 
mav45 ADMIN 
klo26 PROD,ADMIN,QA 

編輯：我添加了一個與條款與一些樣本數據，這會運行我沒有任何問題，儘管我註釋掉了last_name和first_name列，因爲它們對最終查詢沒有影響，我在連接條件中放了一些括號。

也許它會支付開始與我已經得到上面的查詢，檢查它最初適用於您，並適當修改它。