如何在ASP.net程序的根目錄中的以前生成的文件中使用LINQ讀取XML文件(XMLfile.xml)。每個元素都存在於我已創建的XML文件中(請參閱下面的摘錄)。使用LINQ讀取XML文件
XDocument xmlElements = XDocument.Parse(System.IO.File.ReadAllText(Server.MapPath("XMLfile.xml")));
var elements = from data in xmlElements.Descendants("/NewDataSet/Table")
select new
{
Number0 = (int)data.Element("Number"),
Name0 = (string)data.Element("Name"),
a0 = (double)data.Element("a"),
e0 = (double)data.Element("e"),
i0 = (double)data.Element("i"),
N0 = (double)data.Element("N"),
w0 = (double)data.Element("w"),
Pyrs0 = (double)data.Element("Pyrs"),
mm0 = (double)data.Element("mm"),
MA0 = (double)data.Element("MA0")
};
foreach (var element in elements)
{
m = m + 1;
num[m] = element.Number0;
nam[m] = element.Name0;
a1[m] = element.a0;
ecc[m] = element.e0;
i[m] = element.i0;
N[m] = element.N0;
w[m] = element.w0;
Pyrs[m] = element.Pyrs0;
mm[m] = element.mm0;
MA0[m] = element.MA0;
}
XMLfile.xml
<?xml version="1.0" standalone="yes"?>
<NewDataSet>
<Table>
<Number>1</Number>
<Name>Ceres</Name>
<a>2.7681117</a>
<e>0.0757544</e>
<i>10.59166</I>
<N>80.3218024</N>
<w>72.73324</w>
<Pyrs>4.61</Pyrs>
<mm>0.2140072</mm>
<MA0>181.38143</MA0>
</Table>
<Table>
<Number>2</Number>
<Name>Pallas</Name>
<a>2.7723622</a>
<e>0.2310236</e>
<i>34.84095</i>
<N>173.0882785</N>
<w>309.98943</w>
<Pyrs>4.62</Pyrs>
<mm>0.2135153</mm>
<MA0>163.60434</MA0>
</Table>
...
</NewDataSet>
請解釋您的問題,您只是粘貼了您的代碼,但沒有說明如果您有任何問題。 – Gusman
XDocument xDoc = XDocument.Load(Server.MapPath(「XMLFile.xml」)); – Hakunamatata
System.Xml.dll中發生類型'System.Xml.XmlException'的異常,但未在用戶代碼中處理 附加信息:名稱不能以'/'字符開頭,十六進制值爲0x2F。 – losopha