2012-05-30 1035 views

回答

11

代替select *使用select table.columnnametablename.*

+4

,但我有20列,必須有一個更簡單方式,也許分配與ID爲AS –

+0

'tablename。*'的列爲我做了。我只需要從一個表中選擇。謝謝! – JedatKinports

-1
SELECT * 
      FROM [3D_Benchmarks] 
      JOIN [3D_Slugs] ON [3D_Benchmarks].Id = [3D_Slugs].BenchmarkId) AS tb 

3D_Benchmarks有id列,3D_Slugs也有id列。

爲explame:[3D_Benchmarks] .ID爲輔助,3D_Slugs.id作爲投標